Dynamic Proof of SSS Triangle Congruence Theorem
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This example demonstrates the dynamic proof of the SSS Triangle Congruence Theorem. It involves core mathematical concepts such as triangle congruence criteria, geometric transformations, and vector operations. The construction utilizes GeoGebra commands/objects like Circle, Intersect, Segment, Polygon, Point, Line, Angle, Dilate, Vector, Translate, Rotate, Mirror, Ray, Min, and CircleSector. It is suitable for high school students and teachers learning geometric proofs and dynamic geometry.
GeoGebra Commands & Parameters
Circle(A, a) → d_1Intersect(d_1, e) → B, CCircle(C, b) → fSegment(A, C) → gCircle(A, c) → kIntersect(k, f) → F, G, ,Segment(C, F) → hSegment(F, A) → iPolygon(A, C, F) → poly1, f_1, a_1, c_1Circle(D, i) → pPoint(p) → ESegment(D, E) → nCircle(D, g) → qCircle(E, h) → rIntersect(q, r, 2) → HSegment(D, H) → sSegment(H, E) → tLine(A, n) → g_1Point(g_1) → IAngle(I, A, F) → αDilate(A, If[0 < o ≤ 1, 1 - o, 0], D) → A'Vector(A, A') → uTranslate(F, u) → F'Translate(A, u) → A'_1Segment(F', A'_1) → i'Rotate(F', If[1 < o ≤ 2, ((-(o - 1)) * α), (-α)], D) → F''Rotate(A'_1, If[1 < o ≤ 2, ((-(o - 1)) * α), (-α)], D) → JSegment(F'', J) → i''Dilate(A, If[2 < o ≤ 3, 3 - o, 0], D) → A'_2Vector(A, A'_2) → vTranslate(A, v) → A'_3Translate(C, v) → C'Segment(A'_3, C') → g'Line(D, g) → h_1Point(h_1) → KAngle(H, D, K) → βRotate(A'_3, If[3 < o ≤ 4, ((-(o - 3)) * β), (-β)], D) → LRotate(C', If[3 < o ≤ 4, ((-(o - 3)) * β), (-β)], D) → C''Segment(L, C'') → g''Line(C, t) → i_1Point(i_1) → MAngle(M, C, F) → γDilate(C, If[4 < o ≤ 5, 5 - o, 0], C'') → C'_1Vector(C, C'_1) → wTranslate(C, w) → C'_2Translate(F, w) → F'_1Segment(C'_2, F'_1) → h'Rotate(C'_2, If[5 < o ≤ 6, ((-(o - 5)) * γ), (-γ)], C'') → NRotate(F'_1, If[5 < o ≤ 6, ((-(o - 5)) * γ), (-γ)], C'') → OSegment(N, O) → h''Line(F, C) → j_1Mirror(A, j_1) → A'_6Mirror(C, j_1) → C'_4Mirror(F, j_1) → F'_3Polygon(A'_6, C'_4, F'_3) → poly1'_1, f'_3, a'_6, c'_4Point(j_1) → SPoint(j_1) → TRay(C'_4, T) → k_1Ray(F'_3, S) → l_1Segment(A'_6, F'_3) → m_1Segment(A'_6, C'_4) → n_1Dilate(F, If[0 < d ≤ 1, 1 - d, 0], E) → F'_2Vector(F, F'_2) → u_1Translate(A'_6, u_1) → PTranslate(C'_4, u_1) → QTranslate(F'_3, u_1) → RPolygon(P, Q, R) → poly2, r_1, p_1, q_1Translate(A'_6, u_1) → UTranslate(C'_4, u_1) → VSegment(U, V) → s_1Translate(A'_6, u_1) → WTranslate(F'_3, u_1) → ZSegment(W, Z) → t_1Translate(C, u_1) → C'_3Translate(F, u_1) → F'_4Segment(C'_3, F'_4) → h'_1Translate(A'_6, u_1) → A_1Translate(F'_3, u_1) → B_1Segment(A_1, B_1) → e_1Line(E, k_1) → f_2Point(f_2) → C_1Angle(C'', E, C_1) → δRotate(P, If[1 < d ≤ 2, ((-(d - 1)) * δ), (-δ)], E) → P'Rotate(Q, If[1 < d ≤ 2, ((-(d - 1)) * δ), (-δ)], E) → Q'Rotate(R, If[1 < d ≤ 2, ((-(d - 1)) * δ), (-δ)], E) → R'Polygon(P', Q', R') → poly2', r', p', q'Rotate(A_1, If[1 < d ≤ 2, ((-(d - 1)) * δ), (-δ)], E) → D_1Rotate(B_1, If[1 < d ≤ 2, ((-(d - 1)) * δ), (-δ)], E) → E_1Segment(D_1, E_1) → g_2Rotate(U, If[1 < d ≤ 2, ((-(d - 1)) * δ), (-δ)], E) → U'Rotate(V, If[1 < d ≤ 2, ((-(d - 1)) * δ), (-δ)], E) → V'Segment(U', V') → h_2Rotate(C'_3, If[1 < d ≤ 2, ((-(d - 1)) * δ), (-δ)], E) → F_1Rotate(F'_4, If[1 < d ≤ 2, ((-(d - 1)) * δ), (-δ)], E) → G_1Segment(F_1, G_1) → i_2Polygon(D, C'', E) → poly3, e_2, d_2, c''Dilate(D, If[2.5 < d ≤ 3.5, 3.5 - d, 0], D_1) → D'Segment(D, D') → j_2Segment(E, C'') → k_2Min(c, k_2 / 2) → o_1Circle(D, (0.3 * o_1)) → c_2Intersect(c_2, i'') → H_1,Intersect(c_2, j_2) → I_1,CircleSector(D, I_1, H_1) → p_2Intersect(j_2, k_2) → J_1Polygon(D, D_1, E) → poly4, e_3, d_3, d_4Dilate(D, If[3.5 < d ≤ 4.5, 4.5 - d, 0], D_1) → D'_1Vector(D, D'_1) → v_1Translate(p_2, v_1) → q_2Angle(E, D_1, D) → εRotate(q_2, If[4.5 < d ≤ 5.5, ((d - 4.5) * (π - ε)), π - ε], D_1) → r_2Intersect(c_2, g'') → K_1, L_1CircleSector(D, K_1, I_1) → s_2Polygon(D, C'', D_1) → poly5, d_5, d_6, c''_1Dilate(D, If[6 < d ≤ 7, 7 - d, 0], D_1) → D'_2Vector(D, D'_2) → w_1Translate(s_2, w_1) → t_2Angle(D, D_1, C'') → ζRotate(t_2, If[7 < d ≤ 8, ((-(d - 7)) * (π - ζ)), (-(π - ζ))], D_1) → c_3Dilate(E, If[8.5 < d ≤ 9.5, 9.5 - d, 0], C'') → E'Segment(E, E') → l_2Segment(E, C'') → m_2Polygon(A, C, F) → poly6, f_3, a_2, c_4Polygon(D, C'', E) → poly7, e_4, d_7, c''_2
AI Drawing Prompt Reference
Draw triangle ABC and prove its congruence with SSS theorem dynamically. First, draw circle A(a) and circle C(b) to determine points B and C. Then, draw triangle AFG. Use transformations like translation, rotation, and dilation to construct triangle A'F'G' and prove its congruence with triangle ABC.
The prompt above was compiled from the original drawing commands and is for reference only.