Circle Through Three Given Points
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CLASS IX CBSE MATHS ACTIVITIES
This example demonstrates the classic geometric construction of a unique circle passing through three given non-collinear points. It illustrates the fundamental theorem that three non-collinear points determine a circle, and highlights the role of perpendicular bisectors in locating the circle's center. The construction uses GeoGebra commands: Point to create three points A, B, C; Segment to form triangle ABC; LineBisector to construct perpendicular bisectors of AB and BC; Intersect to find their intersection D, which is the circumcenter; and Circle to draw the circle centered at D with radius DA. This activity is suitable for middle school and high school students learning geometric constructions and circle properties, and serves as an effective visual aid for teachers explaining the uniqueness of the circumcircle.
GeoGebra Commands & Parameters
Point(Circle[A, a]) → BSegment(A, B) → fPoint(Circle[B, b]) → CSegment(B, C) → gSegment(A, C) → hLineBisector(A, B) → iLineBisector(C, B) → jIntersect(i, j) → DCircle(D, C) → c
AI Drawing Prompt Reference
Draw three non-collinear points and connect them with line segments to form a triangle. Construct the perpendicular bisectors of two of the sides; these bisectors intersect at a point, which is the circumcenter of the triangle. Using this circumcenter as the center and the distance from it to any vertex as the radius, draw a circle that passes through all three points. This circle is the unique circle determined by the three points, illustrating the fundamental geometric property that three non-collinear points define a circle.
The prompt above was compiled from the original drawing commands and is for reference only.