2019年H2M几何题8

GeoGebra 命令及参数

1. Random(1, 3) → a
2. Shuffle({1, 1, 1, 1, 1, 1, 1, 1, 4, 4, 5, 5, 6, 6, 7, 7}) → l14, {1, 6, 1, 4, 6, 5, 7, 5, 1, 7, 1, 1, 1, 1, 1, 4}
3. Shuffle({1, 1, 1, 1, 1, 1, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7}) → l15, {1, 7, 1, 4, 1, 6, 3, 3, 7, 1, 1, 5, 5, 4, 6, 1}
4. Shuffle({1, 1, 1, 1, 3, 3, 3, 3, 4, 4, 5, 5, 6, 6, 7, 7}) → l16, {1, 7, 3, 3, 4, 4, 6, 6, 7, 5, 3, 1, 5, 1, 3, 1}
5. If(g ≟ 1, l14, If[g ≟ 2, l15, l16]) → l17
6. Sum(l17) → n
7. Sequence(Random[1, 16], i, 1, n) → l1
8. Sequence(Element[l17, i], i, 1, 4) → l2
9. Sequence(Element[l17, i], i, 5, 8) → l3
10. Sequence(Element[l17, i], i, 9, 12) → l4
11. Sequence(Element[l17, i], i, 13, 16) → l5
12. Sum(l2) → s1
13. Sum(l3) → s2
14. Sum(l4) → s3
15. Sum(l5) → s4
16. Join({{"Horse"}, l2}) → l7
17. Join({{"Rider"}, l3}) → l8
18. Join({{"Dog"}, l4}) → l9
19. Join({{"Bird"}, l5}) → l10
20. Join({{"Total "}, l6}) → l11
21. TableText(l12, l7, l8, l9, l10, "c|_") → text1
22. TableText(l11, "c|_") → text5
23. TableText(l13, "c|_") → text6
24. IndexOf(4, l17) → b
25. IndexOf(4, l17, b + 1) → c
26. If(a ≟ 1, IndexOf[6, l17], If[a ≟ 2, IndexOf[5, l17], IndexOf[7, l17]]) → d
27. If(a ≟ 1, IndexOf[6, l17, d + 1], If[a ≟ 2, IndexOf[5, l17, d + 1], IndexOf[7, l17, d + 1]]) → e
28. If(Mod[b, 4] ≟ 1, "Orange", If[Mod[b, 4] ≟ 2, "Yellow", If[Mod[b, 4] ≟ 3, "Green", "White"]]) → text12
29. If(b ≤ 4, "Horse", If[b ≤ 8, "Rider", If[b ≤ 12, "Dog", "Bird"]]) → text13
30. If(Mod[c, 4] ≟ 1, "Orange", If[Mod[c, 4] ≟ 2, "Yellow", If[Mod[c, 4] ≟ 3, "Green", "White"]]) → text14
31. If(c ≤ 4, "Horse", If[c ≤ 8, "Rider", If[c ≤ 12, "Dog", "Bird"]]) → text15
32. If(Mod[d, 4] ≟ 1, "Orange", If[Mod[d, 4] ≟ 2, "Yellow", If[Mod[d, 4] ≟ 3, "Green", "White"]]) → text16
33. If(d ≤ 4, "Horse", If[d ≤ 8, "Rider", If[d ≤ 12, "Dog", "Bird"]]) → text17
34. If(Mod[e, 4] ≟ 1, "Orange", If[Mod[e, 4] ≟ 2, "Yellow", If[Mod[e, 4] ≟ 3, "Green", "White"]]) → text18
35. If(e ≤ 4, "Horse", If[e ≤ 8, "Rider", If[e ≤ 12, "Dog", "Bird"]]) → text19
36. If(a ≟ 1, 48 / ((n * (n - 1))), If[a ≟ 2, 40 / ((n * (n - 1))), 56 / ((n * (n - 1)))]) → f