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Congruent Triangles Exercise 6

Congruent Triangles Exercise 6
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2018-04-27 09:51
TriangleTransformationGeometric Construction
In collections Unit 5: Triangle Congruence Naming Congruent Triangles with Reasons Naming Congruent Triangles with Reasons Congruence cases
This example demonstrates how to name congruent triangles and provide reasons. Users can move, rotate, and reflect the triangles. Using GeoGebra commands such as Polygon, Vector, Angle, Intersect, Textfield, Segment, Midpoint, and Rotate, congruent triangles can be constructed and verified. Suitable for middle school geometry learning.

GeoGebra Commands & Parameters

  1. Polygon(A, B, C) → poly1, c, a, b
  2. Vector(P, A) → u
  3. Vector(P, B) → v
  4. Vector(P, C) → w
  5. Polygon(A_1, B_1, C_1) → poly1_1, c_1, a_1, b_1
  6. Vector(P_1, A_1) → u_1
  7. Vector(P_1, B_1) → v_1
  8. Vector(P_1, C_1) → w_1
  9. Angle(B, A, C) → α
  10. Angle(A, C, B) → β
  11. Angle(A_1, C_1, B_1) → γ
  12. Angle(B_1, A_1, C_1) → δ
  13. Intersect(Circle[X_0, Side_b], Circle[Y_0, Side_a]) → Z_0, L, ,
  14. Polygon(X_0, Y_0, Z_0) → poly2, z_0, x_0, y_0
  15. Textfield(text13) → Ans1
  16. Textfield(text14) → Ans2
  17. Segment(D, E) → r
  18. Midpoint(Segment[Intersect[Circle[A, r], b], Intersect[Circle[A, r], c]]) → F
  19. Midpoint(Segment[Intersect[Circle[C, r], a], Intersect[Circle[C, r], b]]) → G
  20. Midpoint(Segment[Intersect[Circle[A_1, r], b_1], Intersect[Circle[A_1, r], c_1]]) → H
  21. Midpoint(Segment[Intersect[Circle[C_1, r], a_1], Intersect[Circle[C_1, r], b_1]]) → I
  22. Angle(A_1, B_1, C_1) → ε
  23. Angle(C, B, A) → ζ
  24. Midpoint(Segment[Intersect[Circle[B, r], a], Intersect[Circle[B, r], c]]) → J
  25. Midpoint(Segment[Intersect[Circle[B_1, r], a_1], Intersect[Circle[B_1, r], c_1]]) → K
  26. Rotate(Translate[Mirror[X_0, x = 0], translate], (-(180° - Angle[Y_0, X_0, Z_0])), (11, 0)) → X_1
  27. Rotate(Translate[Mirror[Y_0, x = 0], translate], (-(180° - Angle[Y_0, X_0, Z_0])), (11, 0)) → Y_1
  28. Rotate(Translate[Mirror[Z_0, x = 0], translate], (-(180° - Angle[Y_0, X_0, Z_0])), (11, 0)) → Z_1