Proof Without Words by Steve Phelps (14)
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Similarity & Right Triangle Trigonometry
Similarity, Right Triangles, and Trigonometry (SRT) Cluster
Proofs Without Words
Proofs Without Words
This is a geometric figure demonstrating the Pythagorean Theorem without words. By dragging points, you can observe the relationship between different geometric elements. It shows that in a right-angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. The construction uses commands such as point, circle arc, segment, mirror, polygon, etc., in GeoGebra. Suitable for middle school and above students to learn geometric proofs.
GeoGebra Commands & Parameters
Point(xAxis) → AIntersect(xAxis, yAxis) → CCircleArc(C, B, A) → cPoint(c) → DSegment(A, D) → aMirror(A, C) → A'Segment(D, A') → bSegment(A', A) → dPolygon(A, D, 4) → poly1, e, f, g, h, E, FPolygon(D, A', 4) → poly2, i, j, k, l, G, HPolygon(A', A, 4) → poly3, m, n, p, q, I, JSegment(D, G) → rSegment(F, D) → sRay(I, A) → tRay(J, A') → a_1Midpoint(s) → KMidpoint(r) → LIntersect(s, t) → MIntersect(r, a_1) → NMirror(M, K) → M'Mirror(N, L) → N'Polygon(D, N, A') → poly4, a', d_1, n_1Polygon(N', H, G) → poly5, g_1, n', h_1Polygon(D, N', H) → poly6, h_2, d_2, n'_1Polygon(G, N, A') → poly7, a'_1, g_2, n_2Polygon(A, M, F) → poly8, f_1, a_2, m_1Polygon(M', E, D) → poly9, d_3, m', e_1Polygon(F, E, M') → poly10, m'_1, f_2, e_2Polygon(M, D, A) → poly11, a_3, m_2, d_4Vector(A', J) → uVector(H, A) → vCentroid(poly4) → OCentroid(poly5) → PTranslate(D, u) → D'Translate(N, u) → N'_1Translate(A', u) → A''Polygon(D', N'_1, A'') → poly4', a'', d', n'_2Translate(N', v) → N''Translate(H, v) → H'Translate(G, v) → G'Polygon(N'', H', G') → poly5', g', n'', h'Vector(M', N'_1) → wTranslate(F, w) → F'Translate(E, w) → E'Translate(M', w) → M''Polygon(F', E', M'') → poly10', m'', f', e'Vector(M, N'') → u_1Translate(M, u_1) → M'_1Translate(D, u_1) → D'_1Translate(A, u_1) → A'_1Polygon(M'_1, D'_1, A'_1) → poly11', a'_2, m'_2, d'_1Circle(A', Segment[F, M]) → c_1Circle(I, Segment[F, M]) → k_1Intersect(c_1, d, 1) → QIntersect(k_1, p, 1) → RPolygon(I, R, D') → poly12, d'_2, i_1, r_1Polygon(Q, A', G') → poly13, g'_1, q_1, a'_3Polygon(D', R, J) → poly14, j_1, d'_3, r_2Polygon(G', Q, A) → poly15, a_4, g'_2, q_2
AI Drawing Prompt Reference
Draw a right triangle ABC with C as the right angle. Use C as the center to draw arcs with A and B as endpoints, intersecting at point D. Connect AD and reflect AD over C to get A'D'. Starting from D, draw vectors u and v, and use them to construct polygons and apply transformations to demonstrate the Pythagorean theorem geometrically.
The prompt above was compiled from the original drawing commands and is for reference only.