Intersection of a Circle and a Prism
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In collections
intersection: surface-surface, curve-curve
intersection: surface-surface, curve-curve
intersection: surface-surface, curve-curve
intersection: surface-surface, curve-curve
This example demonstrates the intersection of a circle and a prism. Key mathematical concepts include solid geometry and coordinate geometry. Using GeoGebra commands such as IntersectPath, Point, and Locus, the intersection of a circle and a prism can be constructed. Suitable for high school mathematics education and learning.
GeoGebra Commands & Parameters
IntersectPath(z = 0, c) → dPoint(d) → ALocus(B, A) → LlocGeomètric1Intersect(fcos, xAxis, (0.5585993153125077, 0)) → CSurface(((R * cos(u)) * sin(v)), ((R * sin(u)) * sin(v)), (R * cos(v)), u, 0, (2 * π), v, 0, π) → bSphere((0, 0), R) → gSurface((((u * R) * cos(t)) * fsin(t)) + (((1 - u) * R) * cos(t)), (((u * R) * sin(t)) * fsin(t)) + (((1 - u) * R) * sin(t)), ((u * R) * fcos(t)), t, x(C), π / 2, u, 0, 1) → lCurveCartesian(((R * cos(t)) * fsin(t)), ((R * sin(t)) * fsin(t)), (R * fcos(t)), t, 0, (2 * π)) → eSequence(CircleArc[(0, 0), POL, e(t), xOyPlane], t, π + x(C), (3 * π / 2), 0.01) → llista2CurveCartesian((R * cos(t)), (R * sin(t)), 0, t, x(C), π / 2) → nSequence(CircleArc[(0, 0), POL, e(t)], t, x(C), π / 2, 0.01) → llista3Sequence(CircleArc[(0, 0), POL, n(t), xOyPlane], t, π / 2, π + x(C), 0.01) → llista4Sequence(CircleArc[(0, 0), POL, n(t)], t, (3 * π / 2), (2 * π) + x(C), 0.01) → llista5CurveCartesian(((R * cos(t)) * fsin(t)), ((R * sin(t)) * fsin(t)), (R * fcos(t)), t, x(C), π / 2) → e1CurveCartesian(((R * cos(t)) * fsin(t)), ((R * sin(t)) * fsin(t)), (R * fcos(t)), t, π + x(C), (3 * π / 2)) → e2Surface((((u * R) * cos(t)) * fsin(t)) + ((1 - u) * (((1 - c3(t)) * x(P1)) + (c3(t) * x(P2)))), (((u * R) * sin(t)) * fsin(t)) + ((1 - u) * (((1 - c3(t)) * y(P1)) + (c3(t) * y(P2)))), ((u * R) * fcos(t)), t, x(C), π / 2, u, 0, 1) → oAngle(P1, (0, 0), P2) → αLine((0, 0), P1) → qSegment(P1, P2) → sgSurface((((u * R) * cos(ang - t)) * fsin(ang - t)) + ((((1 - u) * R) * cos(ang + t)) * fsin(ang + t)), (((u * R) * sin(ang - t)) * fsin(ang - t)) + ((((1 - u) * R) * sin(ang + t)) * fsin(ang + t)), ((u * R) * fcos(ang - t)) + (((1 - u) * R) * fcos(ang + t)), u, 0, 1, t, 0, (2 * π)) → rSurface(x(P1) + (cos(γ) * ((((u * R) * cos(t)) * fsin(t)) + (((1 - u) * R) * cos(t)) - x(P1))) + (sin(γ) * ((((u * R) * sin(t)) * fsin(t)) + (((1 - u) * R) * sin(t)) - y(P1))), y(P1) - (sin(γ) * ((((u * R) * cos(t)) * fsin(t)) + (((1 - u) * R) * cos(t)) - x(P1))) + (cos(γ) * ((((u * R) * sin(t)) * fsin(t)) + (((1 - u) * R) * sin(t)) - y(P1))), ((u * R) * fcos(t)), t, x(C), π / 2, u, 0, 1) → tOrthogonalLine(P1, xOyPlane) → f_1Rotate(n, (-γ), f_1) → n'
AI Drawing Prompt Reference
Draw the intersection of a circle and a prism. First, draw a circle, then draw a prism, find the intersection points between the circle and the prism, and finally construct the intersection shape using these points.
The prompt above was compiled from the original drawing commands and is for reference only.