Congruent Triangles Exercise 3 by Kawa Chan

Congruent Triangles Exercise 3 by Kawa Chan
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2015-11-01 15:19
This example demonstrates how to name congruent triangles and their reasons through moving, rotating, and reflecting. Using GeoGebra commands such as Polygon, Vector, Angle, etc., you can dynamically explore the properties of triangles. Suitable for junior high school geometry learners.

GeoGebra Commands & Parameters

  1. Polygon(A, B, C) → poly1, c, a, b
  2. Vector(P, A) → u
  3. Vector(P, B) → v
  4. Vector(P, C) → w
  5. Polygon(A_1, B_1, C_1) → poly1_1, c_1, a_1, b_1
  6. Vector(P_1, A_1) → u_1
  7. Vector(P_1, B_1) → v_1
  8. Vector(P_1, C_1) → w_1
  9. Angle(B, A, C) → α
  10. Angle(A, C, B) → β
  11. Angle(A_1, C_1, B_1) → γ
  12. Angle(B_1, A_1, C_1) → δ
  13. Intersect(Circle[Y_0, Side_a], Ray[Y_0, Rotate[X_0, 320*°, Y_0]]) → Z_0,
  14. Polygon(X_0, Y_0, Z_0) → poly2, z_0, x_0, y_0
  15. Textfield(text13) → Ans1
  16. Textfield(text14) → Ans2
  17. Segment(D, E) → r
  18. Midpoint(Segment[Intersect[Circle[A, r], b], Intersect[Circle[A, r], c]]) → F
  19. Midpoint(Segment[Intersect[Circle[C, r], a], Intersect[Circle[C, r], b]]) → G
  20. Midpoint(Segment[Intersect[Circle[A_1, r], b_1], Intersect[Circle[A_1, r], c_1]]) → H
  21. Midpoint(Segment[Intersect[Circle[C_1, r], a_1], Intersect[Circle[C_1, r], b_1]]) → I
  22. Angle(A_1, B_1, C_1) → ε
  23. Angle(C, B, A) → ζ
  24. Midpoint(Segment[Intersect[Circle[B, r], a], Intersect[Circle[B, r], c]]) → J
  25. Midpoint(Segment[Intersect[Circle[B_1, r], a_1], Intersect[Circle[B_1, r], c_1]]) → K
  26. Rotate(Translate[Polygon[Mirror[X_0, x = 0], Mirror[Y_0, x = 0], Mirror[Z_0, x = 0]], (20, 0)], 180*°, (14.430456165798875, 1.6001835062956644)) → poly3
  27. Vertex(poly3, 1) → X_1
  28. Vertex(poly3, 2) → Y_1
  29. Vertex(poly3, 3) → Z_1