Congruent Triangles Exercise 3 by Kawa Chan
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This example demonstrates how to name congruent triangles and their reasons through moving, rotating, and reflecting. Using GeoGebra commands such as Polygon, Vector, Angle, etc., you can dynamically explore the properties of triangles. Suitable for junior high school geometry learners.
GeoGebra Commands & Parameters
Polygon(A, B, C) → poly1, c, a, bVector(P, A) → uVector(P, B) → vVector(P, C) → wPolygon(A_1, B_1, C_1) → poly1_1, c_1, a_1, b_1Vector(P_1, A_1) → u_1Vector(P_1, B_1) → v_1Vector(P_1, C_1) → w_1Angle(B, A, C) → αAngle(A, C, B) → βAngle(A_1, C_1, B_1) → γAngle(B_1, A_1, C_1) → δIntersect(Circle[Y_0, Side_a], Ray[Y_0, Rotate[X_0, 320*°, Y_0]]) → Z_0,Polygon(X_0, Y_0, Z_0) → poly2, z_0, x_0, y_0Textfield(text13) → Ans1Textfield(text14) → Ans2Segment(D, E) → rMidpoint(Segment[Intersect[Circle[A, r], b], Intersect[Circle[A, r], c]]) → FMidpoint(Segment[Intersect[Circle[C, r], a], Intersect[Circle[C, r], b]]) → GMidpoint(Segment[Intersect[Circle[A_1, r], b_1], Intersect[Circle[A_1, r], c_1]]) → HMidpoint(Segment[Intersect[Circle[C_1, r], a_1], Intersect[Circle[C_1, r], b_1]]) → IAngle(A_1, B_1, C_1) → εAngle(C, B, A) → ζMidpoint(Segment[Intersect[Circle[B, r], a], Intersect[Circle[B, r], c]]) → JMidpoint(Segment[Intersect[Circle[B_1, r], a_1], Intersect[Circle[B_1, r], c_1]]) → KRotate(Translate[Polygon[Mirror[X_0, x = 0], Mirror[Y_0, x = 0], Mirror[Z_0, x = 0]], (20, 0)], 180*°, (14.430456165798875, 1.6001835062956644)) → poly3Vertex(poly3, 1) → X_1Vertex(poly3, 2) → Y_1Vertex(poly3, 3) → Z_1