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Biscribed Pentakis Dodecahedron (V=32) via Trisection of 11th-Order Segments

Biscribed Pentakis Dodecahedron (V=32) via Trisection of 11th-Order Segments
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2021-04-20 01:49
SequenceSolid GeometryTransformationGeometric ConstructionSlider Animation
This GeoGebra example demonstrates the construction of a new biscribed pentakis dodecahedron with 32 vertices by trisecting the 11th-order segments of an original biscribed pentakis dodecahedron. It explores advanced solid geometry, including dual polyhedra, golden ratio proportions, spherical geometry, and fractal-like iterative subdivision. The construction uses GeoGebra commands such as Sequence, Div, Element, If, Text, Sum, TableText, and IndexOf to generate trisection points and compute geometric properties like volume and sphere radii. Key objects include mm5, m01, A00, r, Volsphere, and interactive sliders/buttons for controlling the iteration. This resource is suitable for high school and university students, as well as enthusiasts interested in polyhedral geometry, 3D modeling, and fractal geometry.

GeoGebra Commands & Parameters

  1. Text("" + p) → txt_p
  2. Sum(Flatten[Sequence[Append[Sequence[Element[txt_p, i], i, m01(k), m02(k)], " "], k, 1, 5]]) → txtUm1
  3. If(bu0, A00, A00d) → A00_0
  4. Length(A00_0) → n
  5. Length(l2) → läl2
  6. Sequence(sgn(Determinant[{Element[A00_0, i1] - Element[A00_0, j], Element[A00_0, i2] - Element[A00_0, j], Element[A00_0, i3] - Element[A00_0, j]}]), j, 1, n) → l01
  7. Length(A00d) → zzz
  8. Sum(Zip[(T * F), T, SysTimeAkt1, F, {1, 1000, 60000, 3600000, 86400000}]) → TimeAbs1
  9. Sum(Zip[(T * F), T, SysTimeAkt2, F, {1, 1000, 60000, 3600000, 86400000}]) → TimeAbs2
  10. Div(TimeRelab, 3600) → H
  11. Div(TimeRelab - (H * 3600), 60) → M
  12. Element(ZwZeit, step) → text10
  13. TableText({Append["a duration", Last[ZwZeit, Min[10, Length[ZwZeit]]]]}, "v") → text2c
  14. Length(A00) → lm1
  15. If(Length[Unique[l01 \ {0}]] ≟ 1, 7, -7) → a7
  16. Sum(Zip[(T * F), T, SysTimeAkt0, F, {1, 1000, 60000, 3600000, 86400000}]) → TimeAbs0
  17. Div(TimeRelab0, 3600) → H0
  18. Div(TimeRelab0 - (H0 * 3600), 60) → M0
  19. Text("" + (TimeRelab0 - (H0 * 3600) - (M0 * 60))) → S0a
  20. Text("" + (TimeRelab - (H * 3600) - (M * 60))) → S
  21. IndexOf(".", S) → index
  22. IndexOf(".", S0a) → indexa
  23. First(S, index + 1) → txtS
  24. First(S0a, indexa + 1) → txtS0a
  25. If(bu0, " ", "d") → txtbuo
  26. Max(Length[A00], Length[A00d]) → maxlä
  27. Element(A00, 24) → m11
  28. TableText({{"\underline{Polyhedron}"}, Append["Vertices: n=", {Length[A00]}], Append["r=", {r}], Append["\bar{r}=", {r_m}], Append["k-gon : k=", mm5a], Append["their\; numbers: n_k=", mm7a], Append["Volume: V=", {Vol_r}], Append["Average\; distance: p=", {txtUm1}]}, "hr ") → text7
  29. TableText({{"\underline{dual\;Polyhedron}"}, Append["Vertices: n=", {Length[A00d]}], Append["r=", {r_d}], Append[" \bar{r_d}= ", {r_md}], Append["k-gon : k=", mm5ad], Append["their\; numbers: n_k=", mm7ad], Append["Volume: V=", {Vold_r}]}, "hr ") → text20

AI Drawing Prompt Reference

Draw a biscribed pentakis dodecahedron with 32 vertices. Construct it by trisecting 11th-order segments and display its dual polyhedron, golden ratio proportions, spherical geometry, and iterative subdivision. Include interactive controls to adjust the iteration count and observe different refinement effects.
The prompt above was compiled from the original drawing commands and is for reference only.