纸盒折叠求最大体积 by Banharn Katkasam
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这个范例演示了如何通过折叠纸盒来求解最大体积的问题。核心数学概念包括立体几何中的体积计算和微积分中的导数与极值。通过使用GeoGebra命令如Function, Segment, Rotate, Line, Intersect等,可以动态展示折叠过程中的几何变换和体积变化。适合高中数学教学和学习,特别是立体几何和微积分部分。
GeoGebra 命令及参数
Function(((x * (length - (2 * x))) * (width - (2 * x))), 0, Vright) → VSegment(B, C) → bRotate(B, α, A) → B'Line(B', A) → sLine(Ax, s) → s1Segment(A, B) → aLine(C, a) → rIntersect(s, r) → DLine(Dy, r) → r1Intersect(r1, b) → CySegment(Dy, Cy) → c1Segment(C, D) → cIntersect(s1, c) → DxSegment(Ax, Dx) → d1Intersect(d1, c1) → D1Line(B, s) → qLine(Bx, q) → q1Intersect(q1, c) → CxSegment(Bx, Cx) → b1Intersect(b1, c1) → C1Line(A, B) → pLine(Ay, p) → p1Intersect(p1, b) → BySegment(Ay, By) → a1Intersect(d1, a1) → A1Intersect(b1, a1) → B1Angle(B, A, B') → βSegment(D, A) → dPolygon(A1, A2a, B2a, B1) → poly1, e, f, g, h_1Polygon(B1, B2b, C2b, C1) → poly2, i, j, k, lPolygon(C1, C2c, D2c, D1) → poly3, c_1, d_1, e_1, f_1Polygon(D1, D2d, A2d, A1) → poly4, m, n, a_1, b_1Derivative(V) → VderRoot(Vder) → tMax_1, tMax_2Min(x(tMax_1), x(tMax_2)) → tMaxSegment(tMax_1, P) → g_1