Sarrus’ Rule for a 3×3 Determinant—Geometric Construction

Sarrus’ Rule for a 3×3 Determinant—Geometric Construction
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2024-09-29 02:06
This example demonstrates how to compute a 3×3 determinant using Sarrus’ Rule in a visual, construction-based way. It builds a geometrical/table-like layout where the determinant is obtained from the products of three downward-diagonal terms minus the products of three upward-diagonal terms, making the sign pattern and term pairing easy to read. The key mathematics includes 3rd-order determinants, the arrangement of matrix coefficients into diagonal terms, and the positive/negative structure of the Sarrus expansion. In GeoGebra, the construction is driven by commands such as TableText to organize coefficient entries, Segment to draw the core structural lines, Translate and Rotate to replicate shifted/rotated components that correspond to diagonal term positions, and CurveCartesian to render coordinate-linked curves if needed for the visualization. Additional commands like Circle and Cylinder support auxiliary visual emphasis of the configuration, while Length can be used for geometric measurements related to the setup. The final determinant value is computed with the det operation, using explicitly constructed intermediate objects (e.g., the various d*, r*, c* sets) to correspond to the determinant’s diagonal product terms. Suitable for high school and early undergraduate linear algebra, especially for classroom demonstrations and conceptual understanding of determinant computation.

GeoGebra Commands & Parameters

  1. TableText(M, "vc", 100, 100) → tab
  2. Segment((-3, 6) + ((-s), s), (3, 0) + (s, (-s))) → d1b
  3. Circle(Point[d1b, t], r) → c1
  4. Segment((-3, 4) + ((-r), r), (3, -2) + (r, (-r))) → d2b
  5. Circle(Point[d2b, t - 2], r) → c2
  6. Translate(c2, (0, 6)) → c2'
  7. Segment((-3, 6), Point[d1b, t]) → r1b
  8. Segment((-3, 2) + ((-r), r), (3, -4) + (r, (-r))) → d3b
  9. Circle(Point[d3b, t - 4], r) → c3
  10. Translate(c3, (0, 6)) → c3'
  11. Segment((-3, 4), If[y(Point[d2b, t - 2]) > 0, Point[d2b, t - 2], (1, 0)]) → r2b
  12. Segment(If[y(Point[d2b, t - 2]) > 0, Point[d2b, t - 2], (1, 6)], (0, 6) + Point[d2b, t - 2]) → r2b'
  13. Segment((-3, 2), If[y(Point[d3b, t - 4]) > 0, Point[d3b, t - 4], (-1, 0)]) → r3b
  14. Segment(If[y(Point[d3b, t - 4]) > 0, Point[d3b, t - 4], (-1, 6)], (0, 6) + Point[d3b, t - 4]) → r3b'
  15. Segment((3, 6) + (s, s), (-3, 0) + ((-s), (-s))) → d4b
  16. Segment((3, 4) + (r, r), (-3, -2) + ((-r), (-r))) → d5b
  17. Segment((3, 2) + (r, r), (-3, -4) + ((-r), (-r))) → d6b
  18. Circle(Point[d4b, t - 6], r) → c4
  19. Segment((3, 6), Point[d4b, t - 6]) → r4b
  20. Circle(Point[d5b, t - 8], r) → c5
  21. Segment((3, 4), If[y(Point[d5b, t - 8]) > 0, Point[d5b, t - 8], (-1, 0)]) → r5b
  22. Segment(If[y(Point[d5b, t - 8]) > 0, Point[d5b, t - 8], (-1, 6)], (0, 6) + Point[d5b, t - 8]) → r5b'
  23. Translate(c5, (0, 6)) → c5'
  24. Circle(Point[d6b, t - 10], r) → c6
  25. Segment((3, 2), If[y(Point[d6b, t - 10]) > 0, Point[d6b, t - 10], (1, 0)]) → r6b
  26. Segment(If[y(Point[d6b, t - 10]) > 0, Point[d6b, t - 10], (1, 6)], (0, 6) + Point[d6b, t - 10]) → r6b'
  27. Translate(c6, (0, 6)) → c6'
  28. Segment((-2.5, 5.5), (2.5, 0.5)) → d1a
  29. Segment((2.5, 5.5), (-2.5, 0.5)) → d4a
  30. Translate(d1a, (0, -2)) → d2a
  31. Translate(d1a, (0, -4)) → d3a
  32. Translate(d4a, (0, -2)) → d5a
  33. Translate(d4a, (0, -4)) → d6a
  34. Segment(Point[d1a, 0], Point[d1a, t]) → r1a
  35. Segment(Point[d2a, 0], Point[d2a, t - 2]) → r2a
  36. Segment(Point[d3a, 0], Point[d3a, t - 4]) → r3a
  37. Segment(Point[d4a, 0], Point[d4a, t - 6]) → r4a
  38. Segment(Point[d5a, 0], Point[d5a, t - 8]) → r5a
  39. Segment(Point[d6a, 0], Point[d6a, t - 10]) → r6a
  40. TableText(M', "vc", 100, 100) → tab'
  41. Translate((-3.06, 6.06), ((0, -6) * Min[t + 1, 1])) → Pu1
  42. Length(t4) → l4
  43. Length(t5) → l5
  44. Length(t6) → l6
  45. CurveCartesian((3 * k / pi) - 2, (-2 * sin(k + (2 * pi / 3))), (2 * cos(k + (2 * pi / 3))), k, 0, ((4 * pi / 3) * Min[1, t - 2])) → h2
  46. CurveCartesian((3 * k / pi) - 2, (-2 * sin(k + (4 * pi / 3))), (2 * cos(k + (4 * pi / 3))), k, 0, ((4 * pi / 3) * Min[1, t - 4])) → h3
  47. CurveCartesian((-3 * k / pi) + 2, (-2 * sin(k)), (2 * cos(k)), k, 0, ((4 * pi / 3) * Min[1, t - 6])) → h4
  48. CurveCartesian((-3 * k / pi) + 2, (-2 * sin(k + (2 * pi / 3))), (2 * cos(k + (2 * pi / 3))), k, 0, ((4 * pi / 3) * Min[1, t - 8])) → h5
  49. CurveCartesian((-3 * k / pi) + 2, (-2 * sin(k + (4 * pi / 3))), (2 * cos(k + (4 * pi / 3))), k, 0, ((4 * pi / 3) * Min[1, t - 10])) → h6
  50. CurveCartesian((3 * k / pi) - 2, (-2 * sin(k)), (2 * cos(k)), k, 0, ((4 * pi / 3) * Min[1, t])) → h1
  51. Rotate((-2, 0, 2), 120°, xAxis) → P_{2,1}
  52. Rotate((0, 0, 2), 120°, xAxis) → P_{2,2}
  53. Rotate((2, 0, 2), 120°, xAxis) → P_{2,3}
  54. Rotate((-2, 0, 2), 240°, xAxis) → P_{3,1}
  55. Rotate((0, 0, 2), 240°, xAxis) → P_{32}
  56. Rotate((2, 0, 2), 240°, xAxis) → P_{3,3}
  57. Cylinder((-2.5, 0, 0), (-2.5 + 5 / 3, 0, 0), 2) → a1, c, d, b
  58. Cylinder((-2.5 + 5 / 3, 0, 0), (-2.5 + 10 / 3, 0, 0), 2) → a2, e, f, g
  59. Cylinder((-2.5 + 10 / 3, 0, 0), (2.5, 0, 0), 2) → a3, h, k, i

AI Drawing Prompt Reference

Draw a 3x3 determinant using Sarrus' rule. First, create a 6x3 table and input the matrix elements. Then, draw two diagonals connecting the top-left to bottom-right and top-right to bottom-left. Next, draw circles and arcs around these diagonals to represent the determinant calculation process. Finally, use these circles and arcs to show the steps of the determinant calculation and display the determinant value.
The prompt above was compiled from the original drawing commands and is for reference only.