Pythagorean Theorem Proof - Square
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This example demonstrates the proof of the Pythagorean Theorem. By constructing squares and triangles, it shows that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides. Commands used include Polygon, Segment, Intersect, Point, Rotate, Ray, OrthogonalLine, Vector, Translate, suitable for middle school and above students to learn geometric proofs.
GeoGebra Commands & Parameters
Polygon(A, B, 4) → poly1, f, g, h, i, C, DSegment(A, C) → jSegment(B, D) → kIntersect(j, k) → MPoint(i) → ERotate(E, 90°, M) → FRay(F, B) → lOrthogonalLine(X, l) → a_8Rotate(F, 90°, M) → GRotate(G, 90°, M) → HSegment(F, G) → c_5Segment(G, H) → c_3Segment(H, E) → c_4Segment(F, B) → a_1Segment(B, G) → b_8Segment(G, C) → a_3Segment(C, H) → b_3Segment(H, D) → a_4Segment(D, E) → b_4Vector(X, Y) → uTranslate(F, u) → F'Translate(B, u) → B'Segment(F', B') → a_5Translate(A, u) → A'Translate(F, u) → F'_1Segment(A', F'_1) → b_7Translate(D, u) → D'Translate(E, u) → E'Segment(D', E') → b_5Polygon(D', A', 4) → poly2, m, n, p, q, I, JSegment(B', J) → rSegment(J, D') → sSegment(A', E') → tPolygon(F', B', 4) → poly3, a_7, b_1, c_1, d, K, LSegment(F', L) → eSegment(L, K) → f_1Segment(L, E') → g_1Segment(B', K) → a_6Segment(K, J) → i_1OrthogonalLine(L, s) → j_1Intersect(j_1, s) → NSegment(D', N) → b_6Segment(N, J) → l_1Segment(L, N) → m_1Segment(F', E') → n_1Segment(L, J) → p_1Segment(A, F) → bSegment(F, E) → cSegment(E, A) → aPolygon(E, F, G, H) → c_2, e_1, f_2, g_2, h_1Polygon(F', B', K, L) → a_2, f', b', k_1, l_2Polygon(E', L, N, D') → b_2, e', l_3, n_2, d'
AI Drawing Prompt Reference
Draw a right triangle ABC with AB as one of the legs, BC as the hypotenuse, and AC as the other leg. Construct squares on each side of the triangle. Rotate and translate these triangles to form two new squares, one with side length equal to BC and the other with side length equal to half the sum of AB and AC. Demonstrate the geometric proof of the Pythagorean theorem by showing that the area of the square on the hypotenuse is equal to the sum of the areas of the squares on the other two sides.
The prompt above was compiled from the original drawing commands and is for reference only.