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Fraction Division: a ÷ b (Partitive)

Fraction Division: a ÷ b (Partitive)
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2018-10-21 21:58
Geometric Construction
This example demonstrates the understanding of fraction division a ÷ b in the context of partitive division, showing that a ÷ b = a/b. It involves core mathematical concepts like fraction division and partitive division. GeoGebra commands and objects such as Point, Segment, Sequence, Polygon, and GCD are used in the construction. Suitable for middle school mathematics education to help students grasp the geometric meaning of fraction division.

GeoGebra Commands & Parameters

  1. Point(Segment[(x(D) + 2 / 5, y(D)), (x(D) + 1, y(D))]) → S
  2. Segment(A, (x(A) + 1, y(A))) → l1
  3. Point(Segment[(x(A) + 1 / 5, y(A)), (x(A) + 1, y(A))]) → P
  4. Segment(B, (x(B) + 1, y(B))) → l2
  5. Point(Segment[(x(B) + 2 / 6, y(B)), (x(B) + 1, y(B))]) → Q
  6. Point(Segment[(x(C) + 1 / 6 - 0.0050, y(C)), (x(Q) - 1 / 6, y(C))]) → R
  7. Segment(C, (x(C) + 1, y(C))) → l3
  8. Sequence(Circle[(2.5 * (i - 1), 0), 1], i, 1, a) → list1
  9. Sequence(Segment[(2.5 * a, 0), (2.5 * a - sin(j * θ), cos(j * θ))], j, 1, c - 1) → list2
  10. Segment(D, (x(D) + 1, y(D))) → l4
  11. Polygon((-0.5, -3.24), (1, -3.24), (1, -1.24), (-0.5, -1.24)) → poly1, e, g, h, i
  12. GCD(a, d) → k
  13. Segment(A, P) → j
  14. Segment(C, R) → l
  15. Segment(B, Q) → m
  16. Segment(D, S) → n
  17. Point(Segment[(x(A_1) + 1 / 7, y(A_1)), (x(A_1) + 1, y(A_1))]) → P_1
  18. Segment(A_1, P_1) → j_1
  19. Point(Segment[(x(D_1) + 2 / 5, y(D_1)), (x(D_1) + 1, y(D_1))]) → S_1
  20. Point(Segment[(x(A_2) + 1 / 7, y(A_2)), (x(A_2) + 1, y(A_2))]) → P_2
  21. GCD(a_1, d_1) → k_1
  22. Segment(A_2, P_2) → j_2
  23. Segment(D_1, S_1) → n_1
  24. Point(Segment[(x(D_2) + 2 / 5, y(D_2)), (x(D_2) + 1, y(D_2))]) → S_2
  25. Point(Segment[(x(A_3) + 1 / 7, y(A_3)), (x(A_3) + 1, y(A_3))]) → P_3
  26. GCD(a_2, d_2) → k_2
  27. Segment(A_3, P_3) → j_3
  28. Segment(D_2, S_2) → n_2
  29. Sequence(Sequence[CircleSector[(-1 * f * sin((2 * k - 1) * θ / 2) + 2.5 * (m - 1), f * cos((2 * k - 1) * θ / 2)), (-1 * f * sin((2 * k - 1) * θ / 2) - sin((k - 1) * θ) + 2.5 * (m - 1), f * cos((2 * k - 1) * θ / 2) + cos((k - 1) * θ)), (-1 * f * sin((2 * k - 1) * θ / 2) - sin(k * θ) + 2.5 * (m - 1), f * cos((2 * k - 1) * θ / 2) + cos(k * θ))], k, 1, 1], m, 1, a) → list4
  30. Sequence(Sequence[CircleSector[(f * sin((2 * k - 1) * θ / 2) + 2.5 * (m - 1), f * cos((2 * k - 1) * θ / 2)), (f * sin((2 * k - 1) * θ / 2) + sin(k * θ) + 2.5 * (m - 1), f * cos((2 * k - 1) * θ / 2) + cos(k * θ)), (f * sin((2 * k - 1) * θ / 2) + sin((k - 1) * θ) + 2.5 * (m - 1), f * cos((2 * k - 1) * θ / 2) + cos((k - 1) * θ))], k, 1, b], m, 1, a) → list3