正方形纸片折成开式纸盒的体积优化问题
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①本范例演示从正方形纸片各角剪去小正方形后折成开式纸盒的体积变化过程;②涉及核心数学概念包括体积计算、几何变换、最值优化;③构造中运用了多边形绘制(Polygon)、交点计算(Intersect)、线段(Line)、棱柱(Prism)、展开图(Net)、体积计算(Volume)、文本显示(Textfield)及条件判断(If)等命令;④适合高中阶段立体几何与微积分教学,用于理解实际应用中的最值问题。
GeoGebra 命令及参数
Polygon((0, 0), (k, 0), 4) → poly1Intersect(xAxis, yAxis) → BLine(E, G) → bLine(F, H) → cLine(E, F) → dLine(G, H) → eIntersect(d, poly1) → I, JIntersect(e, poly1) → K, LIntersect(b, poly1) → M, NIntersect(c, poly1) → O, PSegment(K, L) → gSegment(M, N) → hSegment(O, P) → iPolygon(I, E, G, K) → poly2, i_1, e_1, g_1, k_3Polygon(E, F, H, G) → poly3, e_2, f_1, h_1, g_2Polygon(M, O, F, E) → poly4, m, o, f_2, e_3Polygon(F, J, L, H) → poly5, f_3, j, l_3, h_2Polygon(G, H, P, N) → poly6, g_3, h_3, p, nSegment(A, C) → qSegment(A, B) → rSegment(C, D) → sSegment(B, D) → tSegment(I, E) → a_1Segment(K, G) → b_1Segment(G, N) → c_1Segment(H, P) → d_1Segment(H, L) → j_1Segment(F, J) → k_1Segment(F, O) → l_1Segment(M, E) → m_1Polygon(A, I, E, M) → poly7, a_2, i_2, e_4, m_2Polygon(K, G, N, C) → poly8, k_2, g_4, n_1, c_2Polygon(H, L, D, P) → poly9, h_4, l_2, d_2, p_1Polygon(O, F, J, B) → poly10, o_1, f_4, j_2, b_2Polygon(E, F, H, G) → poly11, q_1, r_1, s_1, t_1Prism(poly11, a) → u, Q, edgeBQ, edgeAR, edgeCS, edgeDT, edgeQR, edgeRS, edgeST, edgeQT, R, S, T, faceABQR, faceACSR, faceCDTS, faceBDTQ, faceQRSTNet(u, fold) → v, U, F_1, G_1, H_1, I_1, J_1, faceUVWZ, face1, face3, face4, face2, V, face5, edgeUV, edgeVW, edgeWZ, edgeUZ, edge1, edge9, edge3, edge4, edge12, W, edge5, edge6, edge13, edge7, edge8, edge14, edge2, edge11, edge15, edge10, Z, A_1, B_1, C_1, D_1, E_1Segment(O, B) → n_2Segment(B, J) → p_2Volume(u) → wSegment(E, F) → q_2Textfield(f) → inputBox1If(k ≟ 12, Text[k, S_1], Text["k", S_1]) → text5If(k ≟ 12, Text[k, T_1], Text["k", T_1]) → text6
AI 绘图提示语参考
从一张12厘米乘12厘米的正方形卡片开始,在每个角剪去一个边长为k的小正方形。然后将剪下的部分折叠起来,形成一个无盖的盒子。接下来需要计算盒子的体积,并找到使体积最大的k值。过程中要确保所有步骤都基于几何变换和优化原理。
以上提示语为根据原始绘图命令整理而来,仅供参考。