Sicherman Dice 因式分解证明
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①本范例演示了如何通过因式分解证明 Sicherman Dice 的唯一性;②涉及的核心数学概念包括因式分解、多项式系数、概率统计;③作图要点——从下方『构造摘要』提炼用到了 Factor, Polynomial, Coefficients, Flatten, Sequence, TableText, Sum 等GeoGebra命令/对象;④适合高中及以上数学爱好者学习概率论与代数应用。
GeoGebra 命令及参数
Factor(r) → tPolynomial(t) → ttCoefficients(tt) → l2Flatten(Sequence[Sequence[j, i, 1, Element[l2, j]], j, 1, Length[l2]]) → l4Factor(q) → sPolynomial(s) → ssCoefficients(ss) → l1Flatten(Sequence[Sequence[j, i, 1, Element[l1, j]], j, 1, Length[l1]]) → l3Sequence(Sequence[Element[l5, i] + Element[l6, j], i, 1, Length[l3]], j, 1, Length[l4]) → m1Sequence(Sequence[If[i ≟ 0 ∧ j ≟ 0, "+", If[i ≟ 0, "" + (Element[l6, j]), If[j ≟ 0, "" + (Element[l5, i]), "" + (Element[m1, j, i])]]], i, 0, Length[l3]], j, 0, Length[l4]) → m2TableText(m2, "_01000000000000000000000000000000000000|01000000000000000000000000000000000000") → text8Sum(Coefficients[ss]) → sumSSSum(Coefficients[tt]) → sumTT