探索SSA条件下的三角形构造 by Ted Coe
几何画板及绘图内容加载中,请稍等……
所属专题
Congruence (CO) Cluster
Congruence (Vol 1)
Congruence (Vol 1) Over 80 Resources
CCSS High School: Geometry (Congruence) Volume 1 S N ATTAR
Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
CCSS High School: Geometry (Congruence) Volume 1
这个范例演示了为什么SSA(两边及其夹角)不能确定三角形的全等。它涉及的核心数学概念是三角形全等的条件。通过使用GeoGebra命令如Circle, Ray, Intersect, Angle, Segment等,可以构造出不同情况下的三角形。适合高中几何学习者和教师使用。
GeoGebra 命令及参数
Circle(A, b) → eRay(A, C) → dIntersect(e, d) → K,Ray(A, B) → cAngle(B, A, C) → βSegment(A, D) → fIntersect(d, f) → EIntersect(d, f) → FCircle(D, a) → gIntersect(g, c) → G, HSegment(D, G) → hSegment(D, H) → iOrthogonalLine(D, c) → jIntersect(g, j, 1) → IIntersect(j, c) → JDistance(D, J) → kSegment(D, I) → lDistance(D, I) → mDistance(D, I) → Distance[D, J]Polygon(A, G, D) → poly1, d_1, a_1, g_1Polygon(A, H, D) → poly2, d_2, a_2, h_1Angle(D, G, A) → γAngle(D, H, A) → δ
AI 绘图提示语参考
绘制两个三角形,它们共享一个底边AD,且顶点A和D的夹角分别为γ和δ。首先画出底边AD,然后以D为圆心,画两个不同半径的圆,分别与顶点A和D的夹线相交,形成两个三角形。注意观察这两个三角形是否全等,以理解SSA条件下的三角形构造特点。
以上提示语为根据原始绘图命令整理而来,仅供参考。