角度为5π/4的终边与单位圆交点坐标
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本示例演示角度为5π/4的终边与单位圆的交点坐标。涉及的核心数学概念包括单位圆、正弦和余弦函数。通过使用GeoGebra命令如Circle、Segment、Angle等,可以动态展示角度与坐标的关系。适合高中数学教学和学习。
GeoGebra 命令及参数
LaTeX(steps) → counterCircle((0, 0), 1) → cLaTeX("\text{0 radians}") → zeroLaTeX("\text{Sketch the angle.}") → text3If(angleNum / angleDen < 1, Sequence[i / angleDen, i, 1, angleDen - 1], Sequence[1 + i / angleDen, i, 1, angleDen - 1]) → list1Zip((cos((a * π)), sin((a * π))), a, list1) → list2Zip(Segment[(0, 0), a], a, list2) → list3Segment((0, 0), C) → aSegment((0, 0), (1, 0)) → bAngle(A, (0, 0), C) → θIf(0 < factor ≤ 0.5, LaTeX["\text{I}"], If[0.5 < factor ≤ 1, LaTeX["\text{II}"], If[1 < factor ≤ 1.5, LaTeX["\text{III}"], LaTeX["\text{IV}"]]]) → quadrantIf(0 < factor ≤ 0.5, LaTeX["\text{The measure of the original angle is the measure of the reference angle.}"], If[0.5 < factor ≤ 1, LaTeX["\text{Subtract the measure of the original angle from π radians to find the }\cr\text{measure of the reference angle.}"], If[1 < factor ≤ 1.5, LaTeX["\text{Subtract π radians from the original angle measure to find the}\cr\text{measure of the reference angle.}"], LaTeX["\text{Subtract the measure of the original angle from 2π radians to find the }\cr\text{measure of the reference angle.}"]]]) → subtractionIf(0 < factor ≤ 0.5, angleNum, If[0.5 < factor ≤ 1, angleDen - angleNum, If[1 < factor ≤ 1.5, angleNum - angleDen, (2 * angleDen) - angleNum]]) → refNumIf(0 < factor ≤ 0.5, Angle[A, (0, 0), C], If[0.5 < factor ≤ 1, Angle[C, (0, 0), B], If[1 < factor ≤ 1.5, Angle[B, (0, 0), C], Angle[C, (0, 0), A]]]) → θ_{ref}LaTeX((((("\theta=\frac{" * angleNum) * "\pi}{") * angleDen) * "} radians")) → ProblemLaTeX((((((("\textcolor{#CC0000}{\sin(\theta_{ref})=\sin\left(\frac{" * refNum) * "}{") * angleDen) * "}\pi\right)\approx") * sinRef) * "}")) → text11LaTeX((((((("\textcolor{#CC0000}{\cos(\theta_{ref})=\cos\left(\frac{" * refNum) * "}{") * angleDen) * "}\pi\right)\approx") * cosRef) * "}")) → text12LaTeX("\text{Determine the coordinates of point }\textcolor{#006633}{C}.") → text14If(0 < factor ≤ 0.5, LaTeX["\text{(+,+)}"], If[0.5 < factor ≤ 1, LaTeX["\text{(-,+)}"], If[1 < factor ≤ 1.5, LaTeX["\text{(-,-)}"], LaTeX["\text{(+,-)}"]]]) → signsIf(0 < factor ≤ 0.5, LaTeX["\textcolor{#006633}{(\cos(\theta),\sin(\theta))}=\textcolor{#CC0000}{(\cos(\theta_{ref}),\sin(\theta_{ref}))}"], If[0.5 < factor ≤ 1, LaTeX["\textcolor{#006633}{(\cos(\theta),\sin(\theta))}=\textcolor{#CC0000}{(-\cos(\theta_{ref}),\sin(\theta_{ref}))}"], If[1 < factor ≤ 1.5, LaTeX["\textcolor{#006633}{(\cos(\theta),\sin(\theta))}=\textcolor{#CC0000}{(-\cos(\theta_{ref}),-\sin(\theta_{ref}))}"], LaTeX["\textcolor{#006633}{(\cos(\theta),\sin(\theta))}=\textcolor{#CC0000}{(\cos(\theta_{ref}),-\sin(\theta_{ref}))}"]]]) → text16LaTeX("\text{Move the slider to solve the problem.}") → text0LaTeX("\text{Sketch a unit circle, and then label π radians and 2π radians.}") → text1LaTeX("\text{A half rotation (180°) is π radians and a full rotation (360°) is 2π radians. }\cr\text{Notice that 0 radians and 2π radians are in the same location on the unit circle, }\cr\text{but represent different angle measures.}") → text2If(angleNum / angleDen < 1, LaTeX[(((((((((((((((((("\frac{" * angleNum) * " π}{") * angleDen) * "}\text{is the same as }\frac{") * angleNum) * "}{") * angleDen) * "} π. \cr\text{In other words, the terminal side is }\frac{") * angleNum) * "}{") * angleDen) * "}\text{ of the way from 0 to π.}\cr\text{Thus, imagine the semicircle between 0 radians and π radians split into ") * angleDen) * " parts }\cr\text{and then sketch the angle }\frac{") * angleNum) * "}{") * angleDen) * "}\text{ of the way around the semicircle.}")], LaTeX[(((((((((((((((((("\frac{" * angleNum) * " π}{") * angleDen) * "}\text{is the same as }\left(1+\frac{") * newNum) * "}{") * angleDen) * "}\right) π. \cr\text{In other words, the terminal side is }\frac{") * newNum) * "}{") * angleDen) * "} \text{ of the way from π to 2π. }\cr\text{Thus, imagine the semicircle between π radians and 2π radians split into ") * angleDen) * " parts }\cr\text{and then sketch the angle }\frac{") * newNum) * "}{") * angleDen) * "}\text{ of the way around the semicircle.}")]) → text4LaTeX("\text{The coordinates of point }\textcolor{#006633}{C}\text{ are given by } \textcolor{#006633}{(\cos(\theta),\sin(\theta))}\text{ which can be evaluated }\cr\text{from the reference angle }\textcolor{#CC0000}{\theta_{ref}}.") → text5LaTeX("\text{Determine }\textcolor{#CC0000}{\sin(\theta_{ref})}\text{ and }\textcolor{#CC0000}{\cos(\theta_{ref})}\text{ in order to determine }\textcolor{#006633}{\sin(\theta)}\text{ and }\textcolor{#006633}{\cos(\theta)}.") → text10LaTeX("\text{Because the reference angle is always between 0 and }\frac{\pi}{2} \text{radians, the sine}\cr\text{and cosine of the reference angle are always non-negative.}") → text13LaTeX((((("\text{Since point }\textcolor{#006633}{C}\text{ and the terminal side lie in quadrant }" * quadrant) * ", \cr\text{the signs of the coordinates of point }\textcolor{#006633}{C}\text{ are } ") * signs) * ".")) → text15LaTeX("\text{Use the buttons below to return to the original problem or}\cr\text{randomly generate a similar practice problem.}") → text18LaTeX("\text{Determine the measure of the reference angle, which is the measure of the}\cr\text{angle between the terminal side and the x-axis. }") → text6LaTeX((((("\text{The terminal side falls in Quadrant } " * quadrant) * ".\cr") * subtraction) * "")) → text7If(0 < factor ≤ 0.5, LaTeX[(((("\textcolor{#CC0000}{frac{" * refNum) * "}{") * angleDen) * "}π \text{ radian(s)}}")], If[0.5 < factor ≤ 1, LaTeX[(((((((((((("\textcolor{#CC0000}{\frac{" * angleDen) * "}{") * angleDen) * "}π -\frac{") * angleNum) * "}{") * angleDen) * "}π =\frac{") * refNum) * "}{") * angleDen) * "}π \text{ radian(s)}}")], If[1 < factor ≤ 1.5, LaTeX[(((((((((((("\textcolor{#CC0000}{\frac{" * angleNum) * "}{") * angleDen) * "}π -\frac{") * angleDen) * "}{") * angleDen) * "}π =\frac{") * refNum) * "}{") * angleDen) * "}π \text{ radian(s)}}")], LaTeX[(((((((((((("\textcolor{#CC0000}{\frac{2(" * angleDen) * ")}{") * angleDen) * "}π -\frac{") * angleNum) * "}{") * angleDen) * "}π =\frac{") * refNum) * "}{") * angleDen) * "}π\text{ radian(s)}}")]]]) → text8LaTeX((((((((("\text{The reference angle for }\frac{" * angleNum) * "\text{ }\pi}{") * angleDen) * "}\text{ radians is }\frac{") * refNum) * "\text{ }\pi}{") * angleDen) * "}\text{ radian(s).}")) → text9LaTeX((("\text{The coordinates of point }\textcolor{#006633}{C}\text{ are approximately } \textcolor{#006633}{" * C) * "}.")) → text17
AI 绘图提示语参考
绘制一个单位圆,并在圆上标记0弧度和2π弧度。画出角度5π/4的终边,它位于第四象限。根据终边的位置,确定参考角,并计算该角的正弦和余弦值。终边与单位圆的交点C的坐标即为所求。
以上提示语为根据原始绘图命令整理而来,仅供参考。