全等三角形练习2
几何画板及绘图内容加载中,请稍等……
本示例演示如何命名全等三角形及其理由。用户可以移动、旋转和反射三角形。通过使用Polygon, Vector, Angle, Intersect, Textfield, Segment, Midpoint, Rotate等GeoGebra命令,可以构造和验证全等三角形。适合初中及以上学生学习几何变换和全等三角形的相关概念。
GeoGebra 命令及参数
Polygon(A, B, C) → poly1, c, a, bVector(P, A) → uVector(P, B) → vVector(P, C) → wPolygon(A_1, B_1, C_1) → poly1_1, c_1, a_1, b_1Vector(P_1, A_1) → u_1Vector(P_1, B_1) → v_1Vector(P_1, C_1) → w_1Angle(B, A, C) → αAngle(A, C, B) → βAngle(A_1, C_1, B_1) → γAngle(B_1, A_1, C_1) → δIntersect(Circle[X_0, Side_b], Circle[Y_0, Side_a]) → Z_0, L, ,Polygon(X_0, Y_0, Z_0) → poly2, z_0, x_0, y_0Textfield(text13) → Ans1Textfield(text14) → Ans2Segment(D, E) → rMidpoint(Segment[Intersect[Circle[A, r], b], Intersect[Circle[A, r], c]]) → FMidpoint(Segment[Intersect[Circle[C, r], a], Intersect[Circle[C, r], b]]) → GMidpoint(Segment[Intersect[Circle[A_1, r], b_1], Intersect[Circle[A_1, r], c_1]]) → HMidpoint(Segment[Intersect[Circle[C_1, r], a_1], Intersect[Circle[C_1, r], b_1]]) → IAngle(A_1, B_1, C_1) → εAngle(C, B, A) → ζMidpoint(Segment[Intersect[Circle[B, r], a], Intersect[Circle[B, r], c]]) → JMidpoint(Segment[Intersect[Circle[B_1, r], a_1], Intersect[Circle[B_1, r], c_1]]) → KRotate(Translate[Mirror[X_0, x = 0], translate], -(180° - Angle[Y_0, X_0, Z_0]), (11, 0)) → X_1Rotate(Translate[Mirror[Y_0, x = 0], translate], -(180° - Angle[Y_0, X_0, Z_0]), (11, 0)) → Y_1Rotate(Translate[Mirror[Z_0, x = 0], translate], -(180° - Angle[Y_0, X_0, Z_0]), (11, 0)) → Z_1
AI 绘图提示语参考
绘制两个全等三角形ABC和A₁B₁C₁,通过点P和P₁分别平移并旋转三角形,构造它们的对应边和角,利用中点和旋转操作,确保三角形全等。首先绘制三角形ABC,然后通过点P平移并旋转得到A₁B₁C₁。
以上提示语为根据原始绘图命令整理而来,仅供参考。