三维立方体展开图
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①本范例演示了立方体的所有展开图及其在三维空间中的折叠效果;②涉及的核心数学概念包括立体几何、多边形构造、空间变换;③作图要点——运用了Sequence(序列)、Point(点)、Sum(求和)、If(条件判断)、Vector(向量)、Rotate(旋转)、Polygon(多边形)等GeoGebra命令与对象;④适合高中阶段学生及空间几何爱好者学习使用。
GeoGebra 命令及参数
Sequence(D + (0, i), i, 0, 10) → LDPoint(LD) → RSum(Lc) → sumcIf(n < 8, (-0.5, 0), (-1, -0.5)) → A_0Vector(A_0, (-0.5, -0.5)) → uRotate(B + (2, 1), (t * π / 2), Line[B + (1, 1), B + (1, 0)]) → B1_2Rotate(B + (2, 2), (t * π / 2), Line[B + (1, 1), B + (1, 0)]) → B1_3Rotate(B + (1, 0), (t * π / 2), Line[F1_3, F1_4]) → F1_2Rotate(B, (t * π / 2), Line[F1_3, F1_4]) → F1_1Polygon(F1_1, F1_2, F1_3, F1_4) → qF1, s011, s012, s013, s014Rotate(B + (1, 3), (t * π / 2), Line[A1_4, A1_3]) → E1_3Rotate(B + (0, 3), (t * π / 2), Line[A1_4, A1_3]) → E1_4Polygon(E1_1, E1_2, E1_3, E1_4) → qE1, e09_1, e09_2, e09_3, e09_4Polygon(B1_1, B1_2, B1_3, B1_4) → qB1, e06_1, e06_2, e06_3, e06_4Rotate(C1_1 + Vector[B1_1, C1_1], (t * π / 2), Line[C1_4, C1_1]) → C1_2Rotate(C1_4 + Vector[B1_1, C1_1], (t * π / 2), Line[C1_4, C1_1]) → C1_3Polygon(C1_1, C1_2, C1_3, C1_4) → qC1, e07_1, e07_2, e07_3, e07_4Rotate(D1_1 + Vector[C1_1, D1_1], (t * π / 2), Line[D1_4, D1_1]) → D1_2Rotate(D1_4 + Vector[C1_1, D1_1], (t * π / 2), Line[D1_4, D1_1]) → D1_3Polygon(D1_1, D1_2, D1_3, D1_4) → qD1, e08_1, e08_2, e08_3, e08_4Polygon(A1_1, A1_2, A1_3, A1_4) → qA1, e05_1, e05_2, e05_3, e05_4Rotate(B1_3 + Vector[B1_2, B1_3], (t * π / 2), Line[B1_4, B1_3]) → E2_3Rotate(B1_4 + Vector[B1_1, B1_4], (t * π / 2), Line[B1_4, B1_3]) → E2_4Polygon(E2_1, E2_2, E2_3, E2_4) → qE2, e092_1, e092_2, e092_3, e092_4Rotate(C1_3 + Vector[C1_2, C1_3], (t * π / 2), Line[C1_4, C1_3]) → E3_3Rotate(C1_4 + Vector[C1_1, C1_4], (t * π / 2), Line[C1_4, C1_3]) → E3_4Polygon(E3_1, E3_2, E3_3, E3_4) → qE3, e093_1, e093_2, e093_3, e093_4Rotate(D1_3 + Vector[D1_2, D1_3], (t * π / 2), Line[D1_4, D1_3]) → E4_3Rotate(D1_4 + Vector[D1_1, D1_4], (t * π / 2), Line[D1_4, D1_3]) → E4_4Polygon(E4_1, E4_2, E4_3, E4_4) → qE4, e094_1, e094_2, e094_3, e094_4Rotate(B1_1 + Vector[B1_4, B1_1], (t * π / 2), Line[B1_2, B1_1]) → F2_1Rotate(B1_2 + Vector[B1_3, B1_2], (t * π / 2), Line[B1_2, B1_1]) → F2_2Polygon(F2_1, F2_2, F2_3, F2_4) → qF2, e012_1, e012_2, e012_3, e012_4If(n ≠ 7, (-2, -1.5), (-2.5, -1.5)) → B_1Polygon(A7_1, A7_2, A7_3, A7_4) → qA7, e067_1, e067_2, e067_3, e067_4Rotate(A7_2 + Vector[A7_1, A7_2], (t * π / 2), Line[(0.5, 0.5), (0.5, -0.5)]) → B7_2Rotate(A7_3 + Vector[A7_4, A7_3], (t * π / 2), Line[(0.5, 0.5), (0.5, -0.5)]) → B7_3Polygon(B7_1, B7_2, B7_3, B7_4) → qB7, f, g, h, iRotate(B7_2 + Vector[B7_1, B7_2], (t * π / 2), Line[B7_3, B7_2]) → C7_2Rotate(B7_3 + Vector[B7_4, B7_3], (t * π / 2), Line[B7_3, B7_2]) → C7_3Polygon(C7_1, C7_2, C7_3, C7_4) → qC7, e077_1, e077_2, e077_3, e077_4Rotate(A7_1 + Vector[A7_4, A7_1], (t * π / 2), Line[A7_2, A7_1]) → F7_1Rotate(A7_2 + Vector[A7_4, A7_1], (t * π / 2), Line[A7_2, A7_1]) → F7_2Polygon(F7_1, F7_2, F7_3, F7_4) → qF7, f7_1, f7_2, f7_3, f7_4Rotate(F7_1 + Vector[F7_2, F7_1], (t * π / 2), Line[F7_1, F7_4]) → D7_1Rotate(F7_4 + Vector[F7_2, F7_1], (t * π / 2), Line[F7_1, F7_4]) → D7_4Polygon(D7_1, D7_2, D7_3, D7_4) → qD7, d7_1, d7_2, d7_3, d7_4Rotate(D7_4 + Vector[D7_2, D7_1], (t * π / 2), Line[D7_1, D7_4]) → E7_4Rotate(D7_1 + Vector[D7_2, D7_1], (t * π / 2), Line[D7_1, D7_4]) → E7_1Polygon(E7_1, E7_2, E7_3, E7_4) → qE7, e7_1, e7_2, e7_3, e7_4Rotate(A7_3 + Vector[A7_2, A7_3], (t * π / 2), Line[A7_4, A7_3]) → E8_3Rotate(A7_4 + Vector[A7_2, A7_3], (t * π / 2), Line[A7_4, A7_3]) → E8_4Polygon(E8_1, E8_2, E8_3, E8_4) → qE8, e8_1, e8_2, e8_3, e8_4Rotate(B7_3 + Vector[B7_2, B7_3], (t * π / 2), Line[B7_4, B7_3]) → E9_3Rotate(B7_4 + Vector[B7_2, B7_3], (t * π / 2), Line[B7_4, B7_3]) → E9_4Polygon(E9_1, E9_2, E9_3, E9_4) → qE9, e9_1, e9_2, e9_3, e9_4Rotate(C7_3 + Vector[C7_2, C7_3], (t * π / 2), Line[C7_4, C7_3]) → E10_3Rotate(C7_4 + Vector[C7_2, C7_3], (t * π / 2), Line[C7_4, C7_3]) → E10_4Polygon(E10_1, E10_2, E10_3, E10_4) → qE10, e10_1, e10_2, e10_3, e10_4Rotate(E9_2 + Vector[E9_4, E9_3], (t * π / 2), Line[E9_3, E9_2]) → C11_2Rotate(E9_3 + Vector[E9_4, E9_3], (t * π / 2), Line[E9_3, E9_2]) → C11_3Polygon(C11_1, C11_2, C11_3, C11_4) → qC11, c11_1, c11_2, c11_3, c11_4
AI 绘图提示语参考
展示一个立方体的所有可能展开图,这些展开图由多个正方形组成,可以折叠成一个立方体。首先绘制一个由多个正方形组成的平面图形,然后通过旋转和平移操作,生成多个类似的展开图,展示它们如何折叠成一个立方体。每个展开图都由四个正方形组成,它们通过共享边连接在一起。
以上提示语为根据原始绘图命令整理而来,仅供参考。