AA Similarity Theorem Proof
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Geometry - Mini Similarity Book
This example demonstrates the proof of the Angle-Angle (AA) Triangle Similarity Theorem using transformational geometry tools. It involves core concepts like angles, congruence, similar triangles, triangle distributions, general quadrilaterals, upper and lower sums or Riemann sums, expected value, and scalene triangles. The construction utilizes commands/objects such as Segment, Circle, Point, Angle, Rotate, Ray, Intersect, Line, Dilate, Vector, Polygon, Translate, and If from GeoGebra. Suitable for high school mathematics education to understand and apply the AA similarity theorem.
GeoGebra Commands & Parameters
Segment(A, B) → aSegment(B, C) → bSegment(C, A) → cCircle(D, (k * a)) → dPoint(d) → ESegment(D, E) → eCircle(E, (k * b)) → fAngle(A, B, C) → αRotate(D, α, E) → D'Angle(D, E, D') → βRay(E, D') → gIntersect(f, g, 1) → FAngle(C, A, B) → γRotate(E, (-γ), D) → E'Angle(E', D, E) → δRay(D, E') → hSegment(D, E') → iSegment(E', E) → jLine(E, D') → lLine(E, D') → nCircle(D, (k * c)) → pRay(D, E') → mIntersect(p, m, 1) → GSegment(E, G) → qSegment(D, G) → rDilate(D, If[0 < s ≤ 1, 1 - s], A) → D'_1Vector(D, D'_1) → uPolygon(A, C, B) → poly1, b_1, a_1, c_1Polygon(D, E, G) → poly2, g_1, d_1, e_1Translate(D, u) → D'_2Translate(E, u) → E'_1Translate(G, u) → G'Polygon(D'_2, E'_1, G') → poly2', g', d'_2, e'_1Vector(D, A) → vTranslate(D, v) → D'_3Translate(E, v) → E'_2Translate(G, v) → G'_1Polygon(D'_3, E'_2, G'_1) → poly2'_1, g'_1, d'_3, e'_2Segment(D'_1, G') → tSegment(E'_1, D'_1) → h_1Segment(A, G'_1) → i_1Segment(G'_1, E'_2) → j_1Segment(E'_2, A) → k_1Angle(C, A, E'_2) → εIf(ε > γ, ε - γ, γ - ε) → ζRotate(D'_3, If[1 < s ≤ 2, ((-(s - 1)) * ζ), (-ζ)], A) → HRotate(E'_2, If[1 < s ≤ 2, ((-(s - 1)) * ζ), (-ζ)], A) → IRotate(G'_1, If[1 < s ≤ 2, ((-(s - 1)) * ζ), (-ζ)], A) → JPolygon(H, I, J) → poly3, j_2, h_2, i_2Segment(A, J) → l_1Segment(A, I) → m_1Segment(I, J) → n_1Dilate(J, If[2 < s ≤ 3, 3 - s, 0], C) → J'Dilate(I, If[2 < s ≤ 3, 3 - s, 0], B) → I'Segment(I', J') → p_1Angle(A, I', J') → ηAngle(A, I, J) → θAngle(D'_2, E'_1, G') → ιAngle(J, A, I) → λAngle(G', D'_1, E'_1) → μPolygon(A, J', I') → poly4, i', a_2, j'Angle(A, I, J) → νSegment(G'_1, E'_2) → q_1Segment(G', E'_1) → f_1Angle(G'_1, A, E'_2) → κAngle(A, E'_2, G'_1) → ξRotate(D'_3, ((s - 1) * ζ), A) → KRotate(D'_3, If[1 < s ≤ 2, ((s - 1) * ζ), ζ], A) → LRotate(E'_2, If[1 < s ≤ 2, ((s - 1) * ζ), ζ], A) → MRotate(G'_1, If[1 < s ≤ 2, ((s - 1) * ζ), ζ], A) → NPolygon(L, M, N) → poly5, n_2, l_2, m_2Dilate(M, If[2 < s ≤ 3, 3 - s, 0], B) → M'Dilate(N, If[2 < s ≤ 3, 3 - s, 0], C) → N'Segment(M', N') → r_1Polygon(A, M', N') → poly6, n', a_3, m'Angle(A, M', N') → οAngle(A, M, N) → ρSegment(A, M) → t_1Segment(M, N) → b_2Segment(A, N) → c_2Angle(B, A, C) → σAngle(G, E, D) → τAngle(N, M, A) → υAngle(N', M', A) → ϕ
AI Drawing Prompt Reference
Draw triangle ABC. Create a circle centered at A and mark a point E on it. Then draw a circle centered at E and mark a point F on it. Connect D to F and rotate triangle DEF so that angle DEF equals angle ABC. Next, draw another circle centered at E and mark a point G on it. Connect D to G and rotate triangle DEG so that angle DEG equals angle ACB. Finally, connect the corresponding vertices to illustrate the proof of the AA similarity theorem.
The prompt above was compiled from the original drawing commands and is for reference only.