旋转曲面:由两函数区域旋转而成
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本范例演示了如何通过旋转y=f(x)和y=g(x)之间的区域,形成旋转曲面。核心数学概念包括函数、积分和旋转。使用了Surface、Textfield、IntegralBetween、Rotate等GeoGebra命令。适合高中及以上学生学习微积分和几何变换。
GeoGebra 命令及参数
Surface(u, c + ((f(u) - c) * cos(v)), ((f(u) - c) * sin(v)), u, a, b, v, 0, n) → OuterHTextfield(c) → InputBox1Surface(u, c + ((h(u) - c) * cos(v)), ((h(u) - c) * sin(v)), u, a, b, v, 0, n) → InnerHIntegralBetween(f, h, a, b) → rSurface(o + ((u - o) * cos(v)), f(u), ((u - o) * sin(v)), u, a, b, v, 0, n) → VerticalOuterSurface(o + ((u - o) * cos(v)), h(u), ((u - o) * sin(v)), u, a, b, v, 0, n) → VerticalInnerSegment((a, 0), (a, h(a))) → g_1Segment((b, h(b), 0), (b, f(b), 0)) → h_1Rotate(h_1, (-n), (b, c, 0), k) → i_1Rotate(g, (-n), k) → g_2Rotate(p, (-n), k) → p_1Segment((a, h(a), 0), (a, f(a), 0)) → j_1Rotate(j_1, (-n), k) → k_1CurveCartesian(a, (f(a) * t) + (h(a) * (1 - t)), 0, t, 0, 1) → wCurveCartesian(b, (f(b) * t) + (h(b) * (1 - t)), 0, t, 0, 1) → b_1Surface(w, n, k) → c_1Mirror(c_1, z = 0) → LeftHSurface(b_1, n, k) → e_1Mirror(e_1, z = 0) → RightHSurface(w, n, f_1) → dSurface(b_1, n, f_1) → eMirror(d, z = 0) → LesserBoundaryVMirror(e, z = 0) → GreaterBoundaryVRotate(p, (-n), f_1) → p_2Rotate(b_1, (-n), f_1) → uRotate(g, (-n), f_1) → g_3Rotate(w, (-n), f_1) → w'Rotate(D, If[0 < n ≤ pi, (-n), -3.14], k) → D'Rotate(E, If[0 < n ≤ pi, (-n), -3.14], k) → E'CircleArc((b, c, 0), E, E') → qCircleArc((b, c, 0), D, D') → tMirror(E, k) → E'_1CircleArc(F, E, E'_1) → d_1CircleArc(F, E, E'_1) → q_1Mirror(D, k) → D'_1Rotate(D'_1, If[pi < n ≤ (2 * pi), (-(n - pi)), 6.28], k) → GCircleArc(F, D', G) → r_1Rotate(E'_1, If[pi < n ≤ (2 * pi), (-(n - pi)), 6.28], k) → HCircleArc(F, E', H) → s_1Rotate(E, If[0 < n ≤ pi, (-n), -3.14], f_1) → E'_2Rotate(D, If[0 < n ≤ pi, (-n), -3.14], f_1) → D'_2Mirror(E, f_1) → E'_3Mirror(D, f_1) → D'_3CircleArc(I, E, E'_2) → t_1CircleArc(J, D, D'_2) → c_2Rotate(D'_3, If[pi < n < (2 * pi), (-(n - pi)), -3.14], f_1) → KRotate(E'_3, If[pi < n < (2 * pi), (-(n - pi)), -3.14], f_1) → LCircleArc(J, D'_3, K) → d_2CircleArc(I, E'_3, L) → e_2Rotate(N, If[0 < n ≤ pi, (-n), -3.14], M, k) → N'Rotate(O, If[0 < n ≤ pi, (-n), -3.14], M, k) → A'CircleArc(M, N, N') → f_2CircleArc(M, O, A') → h_2Mirror(N, k) → N'_1Mirror(O, k) → O'Rotate(N'_1, If[pi < n < (2 * pi), (-(n - pi)), -3.14], k) → PRotate(O', If[pi < n < (2 * pi), (-(n - pi)), -3.14], k) → O''CircleArc(M, O', O'') → k_2CircleArc(M, N'_1, P) → q_2Rotate(N, If[0 < n ≤ pi, (-n), -3.14], I, f_1) → N'_2Rotate(O, If[0 < n ≤ pi, (-n), -3.14], I, f_1) → O'_1CircleArc(Q, N, N'_2) → r_2CircleArc(R, O, O'_1) → s_2Mirror(N, f_1) → N'_3Mirror(O, f_1) → O'_2Rotate(N'_3, If[pi < n ≤ (2 * pi), (-(n - pi)), -3.14], Q, f_1) → SRotate(O'_2, If[pi < n ≤ (2 * pi), (-(n - pi)), -3.14], Q, f_1) → TCircleArc(Q, N'_3, S) → t_2CircleArc(R, O'_2, T) → c_3Textfield(o) → InputBox2Textfield(a) → InputBox3Textfield(b) → InputBox4Textfield(f) → InputBox5Textfield(h) → InputBox6
AI 绘图提示语参考
画一个旋转曲面,由函数f(x)和g(x)之间的区域旋转形成。首先绘制两个函数曲线,然后计算它们之间的积分,接着用积分结果生成旋转曲面。同时,画出两条垂直线段连接函数曲线与x轴,并旋转这些线段以展示旋转过程。最后,将曲面与线段结合,形成完整的旋转体图形。
以上提示语为根据原始绘图命令整理而来,仅供参考。