证明棱锥体积公式 - 立体几何
几何画板及绘图内容加载中,请稍等……
这个范例演示了如何通过几何变换证明棱锥的体积公式。核心数学概念包括立体几何中的棱锥体积计算。通过使用向量、旋转和平移命令,构建棱锥并进行体积证明。适合高中或大学立体几何课程使用。
GeoGebra 命令及参数
Vector((0, 0, 0), (3, 0, 3)) → vPolygon(A, D, E) → poly1, e, a, dPrism(poly1, B) → b, F_1, edgeBF, edgeFG, edgeBG, F, faceABFD, faceDEGF, faceABGE, faceBFG, edgeAB, edgeDF, edgeEGTranslate(B, Vector[(reset * v)]) → B'Translate(C, Vector[(reset * v)]) → C'Translate(F, Vector[(reset * v)]) → F'Translate(E, Vector[(reset * v)]) → E'Translate(Pyramid[Polygon[B, C, F], E], Vector[(reset * v)]) → cTranslate(Pyramid[Polygon[A, B, C, D], E], Vector[(0 * v)]) → fMidpoint(A, E) → GMidpoint(D, E) → HMidpoint(B, F) → IMidpoint(C, F) → JMidpoint(A, B) → KMidpoint(D, C) → LMidpoint(E, F) → MMidpoint(B, C) → NMidpoint(A, D) → OMidpoint(M, L) → PMidpoint(M, K) → QRotate(Prism[Polygon[D, L, P, H], O], 0°, zAxis) → gRotate(Prism[Polygon[A, O, G], K], 0°, zAxis) → hMidpoint(K, L) → RRotate(Prism[Polygon[Q, R, N], P], 0°, zAxis) → iTranslate(M, Vector[(reset * v)]) → M'Translate(P, Vector[(reset * v)]) → P'Translate(Q, Vector[(reset * v)]) → Q'Translate(I, Vector[(reset * v)]) → I'Translate(J, Vector[(reset * v)]) → J'Rotate(Prism[Polygon[I', J', F'], Q'], 0°, zAxis) → jTranslate(N, Vector[(reset * v)]) → N'Rotate(Prism[Polygon[Q', N', I'], P'], 0°, zAxis) → kVector(B, Q) → uSequence(Translate[Dilate[list1, 0.5, B'], Vector[(t * u)]], t, 0, 1) → list1'Sequence(Translate[Dilate[list2, 0.5, B], Vector[(t * u)]], t, 0, 1) → list2'Sequence(Translate[Dilate[list1, 0.25, B'], Vector[(t * u / 2)]], t, 0, 3) → list1''Sequence(Translate[Dilate[list2, 0.25, B], Vector[(t * u / 2)]], t, 0, 3) → list2''Sequence(Translate[Dilate[list1, 0.125, B'], Vector[(t * u / 4)]], t, 0, 7) → list1'''Sequence(Translate[Dilate[list2, 0.125, B], Vector[(t * u / 4)]], t, 0, 7) → list2'''Sequence(Translate[Dilate[list1, 0.0625, B'], Vector[(t * u / 8)]], t, 0, 15) → list1''''Sequence(Translate[Dilate[list2, 0.0625, B], Vector[(t * u / 8)]], t, 0, 15) → list2''''Translate(Pyramid[Polygon[B, C, F], E], Vector[(reset * v)]) → c'Translate(Pyramid[Polygon[A, B, C, D], E], Vector[(0 * v)]) → f'Rotate(Prism[Polygon[D, L, P, H], O], 0°, zAxis) → g'Rotate(Prism[Polygon[A, O, G], K], 0°, zAxis) → h'Rotate(Prism[Polygon[Q, R, N], P], 0°, zAxis) → i'Rotate(Prism[Polygon[I', J', F'], Q'], 0°, zAxis) → j'Rotate(Prism[Polygon[Q', N', I'], P'], 0°, zAxis) → k'
AI 绘图提示语参考
绘制一个金字塔,底面为三角形BCF,顶点为E。通过平移和旋转,构造金字塔的各个面,并证明其体积公式。首先建立向量v,然后构造底面多边形,接着构建金字塔,通过平移金字塔的各个面,旋转金字塔的棱,最后通过缩放和平移,展示金字塔的各个面的缩放效果。
以上提示语为根据原始绘图命令整理而来,仅供参考。