Nefroide:线性函数与椭圆作图示例
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geometriadinamica.es
这个范例展示了如何通过线性函数和椭圆的几何构造来演示数学关系。核心数学概念包括线性函数、椭圆方程和几何作图方法。作图要点涉及使用GeoGebra命令如Segment、Circle、Ellipse和Intersect来构建图形。适合初中或高中数学学习,用于理解函数与几何的结合。
GeoGebra 命令及参数
Segment(Q3, Q4) → p2Point(p2) → P3Segment(P3, Q4) → p4Point(p4) → P4Segment(Q1, Q2) → p1Point(p1) → P1Segment(P1, Q2) → p3Point(p3) → P2OrthogonalLine(C, xAxis) → zz2Circle(C, 0.62) → zz0Intersect(zz0, zz2, 1) → ZZ4Intersect(zz0, zz2, 2) → ZZ3Ellipse(ZZ3, ZZ4, 0.65) → zElipse2Point(zElipse2) → ZIntersect(zElipse2, zz2) → ZZ7, ZZ8Angle(ZZ8, C, Z) → zAngIncOrthogonalLine(C, yAxis) → zz1Intersect(zz0, zz1, 2) → ZZ2Intersect(zz0, zz1, 1) → ZZ1Ellipse(ZZ1, ZZ2, 0.65) → zElipse1Point(zElipse1) → XYIntersect(zElipse1, zz1) → ZZ5, ZZ6Angle(ZZ6, C, XY) → zAngRotSegment(Q5, Q6) → p5Point(p5) → P5Segment(ZZ5, ZZ6) → zz4Segment(ZZ7, ZZ8) → zz3Intersect(zElipse2, zElipse1, 1) → zPunto1Intersect(zElipse2, zElipse1, 4) → zPunto2Segment(zPunto1, zPunto2) → zSeg2CurveCartesian((r / 2.5 * (((cos(α) * ((3 * cos(v)) - cos((3 * v)))) * sin(zAngRot)) + ((sin(α) * ((3 * cos(v)) - cos((3 * v)))) * cos(zAngRot)))), (r / 2.5 * (((((-cos(α)) * ((3 * cos(v)) - cos((3 * v)))) * cos(zAngRot)) * sin(zAngInc)) + (((sin(α) * ((3 * cos(v)) - cos((3 * v)))) * sin(zAngRot)) * sin(zAngInc)) + (((3 * sin(v)) - sin((3 * v))) * cos(zAngInc)))), v, v1, v2) → curva2CurveCartesian((r / 2.5 * (((cos(u) * 2) * sin(zAngRot)) + ((sin(u) * 2) * cos(zAngRot)))), (r / 2.5 * (((((-cos(u)) * 2) * cos(zAngRot)) * sin(zAngInc)) + (((sin(u) * 2) * sin(zAngRot)) * sin(zAngInc)))), u, u1, u2) → curva1CurveCartesian((r / 2.5 * (((cos(u) * ((3 * cos(β - 3.14159 / 2)) - cos((3 * (β - 3.14159 / 2))))) * sin(zAngRot)) + ((sin(u) * ((3 * cos(β - 3.14159 / 2)) - cos((3 * (β - 3.14159 / 2))))) * cos(zAngRot)))), (r / 2.5 * (((((-cos(u)) * ((3 * cos(β - 3.14159 / 2)) - cos((3 * (β - 3.14159 / 2))))) * cos(zAngRot)) * sin(zAngInc)) + (((sin(u) * ((3 * cos(β - 3.14159 / 2)) - cos((3 * (β - 3.14159 / 2))))) * sin(zAngRot)) * sin(zAngInc)) + (((3 * sin(β - 3.14159 / 2)) - sin((3 * (β - 3.14159 / 2)))) * cos(zAngInc)))), u, u1, u2) → a1Sequence(CurveCartesian[(r / 2.5 * (((cos(u) * ((3 * cos(v)) - cos((3 * v)))) * sin(zAngRot)) + ((sin(u) * ((3 * cos(v)) - cos((3 * v)))) * cos(zAngRot)))), (r / 2.5 * (((((-cos(u)) * ((3 * cos(v)) - cos((3 * v)))) * cos(zAngRot)) * sin(zAngInc)) + (((sin(u) * ((3 * cos(v)) - cos((3 * v)))) * sin(zAngRot)) * sin(zAngInc)) + (((3 * sin(v)) - sin((3 * v))) * cos(zAngInc)))), u, u1, u2], v, v1, v2, paso) → list3Sequence(CurveCartesian[(r / 2.5 * (((cos(u) * ((3 * cos(v)) - cos((3 * v)))) * sin(zAngRot)) + ((sin(u) * ((3 * cos(v)) - cos((3 * v)))) * cos(zAngRot)))), (r / 2.5 * (((((-cos(u)) * ((3 * cos(v)) - cos((3 * v)))) * cos(zAngRot)) * sin(zAngInc)) + (((sin(u) * ((3 * cos(v)) - cos((3 * v)))) * sin(zAngRot)) * sin(zAngInc)) + (((3 * sin(v)) - sin((3 * v))) * cos(zAngInc)))), v, v1, v2], u, u1, u2, paso) → list1
AI 绘图提示语参考
画一个几何图形,展示线性函数与椭圆的关系。首先构建两条线段和两个点,然后以其中一个点为圆心画一个圆,与垂直于x轴的直线相交得到两个点。利用这两个点画一个椭圆,再以另一个点为圆心画另一个圆,同样与垂直于x轴的直线相交得到两个点,并以此画另一个椭圆。最后,连接两个椭圆的交点,并绘制两条曲线,展示函数与几何的融合。
以上提示语为根据原始绘图命令整理而来,仅供参考。