圆内接角定理证明练习(圆心在角外)
几何画板及绘图内容加载中,请稍等……
本范例演示圆内接角定理的证明,特别关注圆心位于内接角外部的情况。通过动态可修改的图形,帮助学生发现和理解几何关系。使用了圆、线、交点、旋转、角度等 GeoGebra 命令。适合初中及以上学生学习几何证明。
GeoGebra 命令及参数
Circle(O, B_1) → cPoint(c) → ALine(A, O) → fIntersect(c, f, 2) → DSemicircle(D, A) → dSemicircle(A, D) → ePoint(d) → BCircleArc(O, A, B) → gCircleArc(O, B, D) → hPoint(h) → CSegment(A, B) → iSegment(O, B) → kSegment(O, C) → lSegment(B, C) → jSegment(A, C) → mCircle(A, (0.25 * Distance[O, A])) → pIntersect(p, i, 1) → GIntersect(p, m, 1) → HCircleSector(A, G, H) → qDilate(A, If[0 < a ≤ 1, 1 - a, 0], O) → C'Segment(A, C') → nDilate(O, If[1 < a ≤ 2, 2 - a, 0], D) → A'Segment(O, A') → rRotate(A, If[2 < a ≤ 3, ((-(a - 2)) * π), (-π)], O) → C'_1Segment(O, C'_1) → sAngle(C, O, D) → αRotate(O, If[3 < a ≤ 4, ((-(a - 3)) * α), (-α)], O) → A'_1Rotate(C'_1, If[3 < a ≤ 4, ((-(a - 3)) * α), (-α)], O) → ISegment(A'_1, I) → s'Circle(C, (0.25 * Distance[O, A])) → tIntersect(t, l, 1) → JAngle(O, C, A) → βDilate(A, If[4 < a ≤ 5, 5 - a, 0], C) → C'_2Segment(A, C'_2) → bPolygon(C, O, A) → poly1, c_1, f_1, a_1Rotate(J, If[5.5 < a ≤ 6.5, ((a - 5.5) * β), β], C) → J'CircleSector(C, J, J') → d_1Angle(A, O, B) → γRotate(A, If[7 < a ≤ 8, ((a - 7) * γ), γ], O) → C'_3Rotate(C', If[7 < a ≤ 8, ((a - 7) * γ), γ], O) → C''Segment(C'_3, C'') → n'Polygon(O, A, B) → poly2, e_1, a_2, c_2Segment(O, B) → g_1Circle(B, (0.25 * Distance[O, A])) → h_1Intersect(h_1, g_1, 1) → KAngle(O, B, A) → δRotate(K, If[8.5 < a ≤ 9.5, ((a - 8.5) * δ), δ], B) → K'CircleSector(B, K, K') → k_1Dilate(A, If[0 < o ≤ 1, 1 - o, 0], O) → C'_4Vector(A, C'_4) → vTranslate(q, v) → q'Line(O, b) → i_1Intersect(h, i_1, 1) → LAngle(C, O, L) → εRotate(q', If[1 < o ≤ 2, ((-(o - 1)) * ε), (-ε)], O) → q''Dilate(A, If[2 < o ≤ 3, 3 - o, 0], O) → C'_5Vector(A, C'_5) → wTranslate(q, w) → q'_1Line(O, i) → j_1Intersect(h, j_1, 1) → MAngle(B, O, M) → ζRotate(q'_1, If[2 < o ≤ 3, ((-(o - 2)) * ζ), (-ζ)], C'_5) → p_1CircleArc(O, B, C) → q_1CircleArc(O, C, B) → r_1