用单位立方体构建体积模型
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① 本范例通过堆积单位立方体来直观展示长方体体积的计算模型,用户可动态调整长、宽、高方向上的立方体数量,观察总体积的变化。② 核心数学概念是体积的定义与计算,即长方体体积等于长、宽、高三个维度上单位立方体个数的乘积,同时涉及空间计数与乘法原理。③ 作图要点:利用GeoGebra的SelectedIndex和Sequence命令生成三维网格,通过对象nx、ny、nz控制三个方向的单位立方体数量,并借助l_x、s_x等变量定义每个立方体的位置与尺寸,最终由L_s1、L_b等列表对象组合成完整的长方体模型,配合sp滑块和text1文本显示体积数值。④ 适合小学高年级至初中阶段学习体积概念,也可用于几何教学中的直观演示,帮助学生建立从一维长度到三维体积的认知桥梁。
GeoGebra 命令及参数
SelectedIndex(nx) → l_xSelectedIndex(ny) → l_ySelectedIndex(nz) → l_zSequence(Sequence[Sequence[Polygon[(x(A) + i - 1, y(A) + j - 1, z(A) + k - 1), (x(A) + i, y(A) + j - 1, z(A) + k - 1), (x(A) + i, y(A) + j - 1, z(A) + k), (x(A) + i - 1, y(A) + j - 1, z(A) + k)], i, 1, (l_x * (1 + s_x)), 1 + s_x], j, 1, (l_y * (1 + s_y)), 1 + s_y], k, 1, (l_z * (1 + s_z)), 1 + s_z) → L_{s1}Sequence(Sequence[Sequence[Polygon[(x(A) + i - 1, y(A) + j - 1, z(A) + k - 1), (x(A) + i, y(A) + j - 1, z(A) + k - 1), (x(A) + i, y(A) + j, z(A) + k - 1), (x(A) + i - 1, y(A) + j, z(A) + k - 1)], i, 1, (l_x * (1 + s_x)), 1 + s_x], j, 1, (l_y * (1 + s_y)), 1 + s_y], k, 1, (l_z * (1 + s_z)), 1 + s_z) → L_{b}Sequence(Sequence[Sequence[Polygon[(x(A) + i - 1, y(A) + j - 1, z(A) + k), (x(A) + i, y(A) + j - 1, z(A) + k), (x(A) + i, y(A) + j, z(A) + k), (x(A) + i - 1, y(A) + j, z(A) + k)], i, 1, (l_x * (1 + s_x)), 1 + s_x], j, 1, (l_y * (1 + s_y)), 1 + s_y], k, 1, (l_z * (1 + s_z)), 1 + s_z) → L_{t}Sequence(Sequence[Sequence[Polygon[(x(A) + i - 1, y(A) + j, z(A) + k - 1), (x(A) + i, y(A) + j, z(A) + k - 1), (x(A) + i, y(A) + j, z(A) + k), (x(A) + i - 1, y(A) + j, z(A) + k)], i, 1, (l_x * (1 + s_x)), 1 + s_x], j, 1, (l_y * (1 + s_y)), 1 + s_y], k, 1, (l_z * (1 + s_z)), 1 + s_z) → L_{s3}Sequence(Sequence[Sequence[Polygon[(x(A) + i, y(A) + j - 1, z(A) + k - 1), (x(A) + i, y(A) + j, z(A) + k - 1), (x(A) + i, y(A) + j, z(A) + k), (x(A) + i, y(A) + j - 1, z(A) + k)], i, 1, (l_x * (1 + s_x)), 1 + s_x], j, 1, (l_y * (1 + s_y)), 1 + s_y], k, 1, (l_z * (1 + s_z)), 1 + s_z) → L_{s2}Sequence(Sequence[Sequence[Polygon[(x(A) + i - 1, y(A) + j - 1, z(A) + k - 1), (x(A) + i - 1, y(A) + j, z(A) + k - 1), (x(A) + i - 1, y(A) + j, z(A) + k), (x(A) + i - 1, y(A) + j - 1, z(A) + k)], i, 1, (l_x * (1 + s_x)), 1 + s_x], j, 1, (l_y * (1 + s_y)), 1 + s_y], k, 1, (l_z * (1 + s_z)), 1 + s_z) → L_{s4}