梯形面积计算
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①本范例演示梯形面积的计算方法;②涉及核心数学概念:梯形面积公式、公式应用与推导;③构造要点:使用了Polygon(多边形)、Centroid(重心)、Vector(向量)、Segment(线段)、Angle(角度)等GeoGebra命令/对象;④适合小学5-6年级学生,用于学习和练习梯形面积公式的应用与理解。
GeoGebra 命令及参数
Polygon(A0, A1, A3, A2) → t1, a0, a1, a3, a2Centroid(t1) → AMVector(AM, A0) → v0MSelectedIndex(DropDown6) → input6SelectedIndex(DropDown5) → input5SelectedIndex(DropDown4) → input4SelectedIndex(DropDown3) → input3SelectedIndex(DropDown2) → input2Point(Line[S1 + 0.6, yAxis]) → S2Point(Line[S2, yAxis]) → S3_{9}Point(Line[S2, yAxis]) → S3_{8}Point(Line[S2, yAxis]) → S3_{7}Point(Line[S2, yAxis]) → S3_{6}Point(Line[S2, yAxis]) → S3_{5}Point(Line[S2, yAxis]) → S3_{4}Point(Line[S2, yAxis]) → S3_{3}Point(Line[S2, yAxis]) → S3_{2}Point(Line[S2, yAxis]) → S3_{1}Element({1, 2, 3, 4, 5, 5.5, 6, 7, 8, 9, 10, 11}, step2) → stepIf(step ≟ 5.5, (13.77887, 0.065), (14.08785, 0.70358)) → S5_{6}Element({S5_{1}, S5_{2}, S5_{3}, S5_{4}, S5_{5}, S5_{6}, S5_{7}, S5_{8}, S5_{9}, S5_{9}}, step) → S5Textfield(input1) → Eingabefeld1Textfield(input2) → Eingabefeld2Segment(A2, Intersect[Line[A2, yAxis], a0]) → hTrapezPolygon(C0, C1, C3, C2) → t2, f, g, i, nPoint(Line[F1, xAxis]) → F2Element({S3_{1}, S3_{2}, S3_{3}, S3_{4}, S3_{5}, S3_{6}, S3_{7}, S3_{8}, S3_{9}, S3_{9}}, step) → S3Mirror(S2, Line[S1, xAxis]) → S7Point(Line[FL1, xAxis]) → FL2Point(Line[FL3, xAxis]) → FL4If(choice ≟ 1, {B1, B3, A1, A3}, If[choice ≟ 2, {A2, A0, B2, B0}, {A0, A1, A3, A2}]) → listBlackPolygon(listBlack) → blackSegment(listBlack(2), listBlack(3)) → aSegment(A2, Intersect[Line[A2, yAxis], a0]) → hTextfield(input7) → Eingabefeld7Polygon(A0, A1, A3, A2) → t3, j, k, l, mPoint(Line[A, xAxis]) → BAngle(A2, Intersect[Line[A2, yAxis], Line[A0, xAxis]], A0) → αPoint(Line[F3, xAxis]) → F4LaTeX(step, true, true) → Text18Element({M1, M2, M3, M4}, Mod[turncount, 4] + 1) → MposPoint(Circle[CM, Length[v0M]]) → CD0Vector(AM, A3) → v3MVector(AM, A1) → v1MVector(AM, A2) → v2MAngle(A0, AM, A1) → winkel01Angle(A1, AM, A3) → winkel13Angle(A3, AM, A2) → winkel32Angle(A2, AM, A0) → winkel20Vector(CM, CD0) → vDCentroid(Polygon[C1, C3, C2, C0]) → CDMLength(v0M) → arrowCircleRadiusSegment(arrowCircleMidpoint + (Distance[arrowCircleMidpoint, arrowCirclePoint] * (cos(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] + arrowCircleDistance + arrowCircleAngle), sin(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] + arrowCircleDistance + arrowCircleAngle))), arrowCircleMidpoint + (Distance[arrowCircleMidpoint, arrowCirclePoint] * (cos(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] + arrowCircleDistance + arrowCircleAngle), sin(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] + arrowCircleDistance + arrowCircleAngle))) + (arrowCircleLength * UnitOrthogonalVector[Vector[arrowCircleMidpoint, arrowCircleMidpoint + (Distance[arrowCircleMidpoint, arrowCirclePoint] * (cos(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] + arrowCircleDistance + arrowCircleAngle), sin(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] + arrowCircleDistance + arrowCircleAngle)))]])) → arrowCircleArrow01Segment(arrowCircleMidpoint + (Distance[arrowCircleMidpoint, arrowCirclePoint] * (cos(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] - arrowCircleDistance - arrowCircleAngle), sin(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] - arrowCircleDistance - arrowCircleAngle))), arrowCircleMidpoint + (Distance[arrowCircleMidpoint, arrowCirclePoint] * (cos(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] - arrowCircleDistance - arrowCircleAngle), sin(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] - arrowCircleDistance - arrowCircleAngle))) - (arrowCircleLength * UnitOrthogonalVector[Vector[arrowCircleMidpoint, arrowCircleMidpoint + (Distance[arrowCircleMidpoint, arrowCirclePoint] * (cos(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] - arrowCircleDistance - arrowCircleAngle), sin(Angle[arrowCircleMidpoint + (1, 0), arrowCircleMidpoint, arrowCirclePoint] - arrowCircleDistance - arrowCircleAngle)))]])) → arrowCircleArrow02
AI 绘图提示语参考
在坐标系中先给出一个梯形的四个顶点,按顺序连接形成梯形边形。计算并标出该梯形的重心点,从重心作指向某一顶点的向量以确定后续辅助方向。再在竖直坐标轴上取与两条水平基边对应的投影点,画出与梯形高相关的竖直线段,用作梯形高的度量。最后在图中标注从重心到相邻边方向的三个夹角,包含以顶点方向与边界射线形成的角,并在合适位置放置文本输入框用于选择参数与显示面积计算相关表达式。
以上提示语为根据原始绘图命令整理而来,仅供参考。