特殊三角形(二):30-60-90 三角形与等边三角形的关系
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本范例通过无文字、无角度标注的交互式几何作图,引导学生自主发现 30-60-90 三角形恰好是等边三角形的一半。核心数学概念包括特殊直角三角形的边长比例、对称性以及等边三角形的性质。作图要点:使用 GeoGebra 的 Polygon、Dilate、Segment、Circle、Intersect、CircleSector、Rotate、Vector、Translate、CircleArc、Midpoint 等命令,构造了等边三角形及其内切/外接圆、旋转与平移后的辅助图形,并通过多个点(如 A、B、C、D、E、F、G、H、I、J、K)和线段(a、b、c、d、e、f、g、h、i、j、k)以及圆弧(CircleSector、CircleArc)来展示几何关系。适合中学几何教学,用于直观理解 30-60-90 三角形的性质及其与等边三角形的联系,也可用于探究对称和旋转变换。
GeoGebra 命令及参数
Polygon(A, B, 3) → poly1, a, b, c, CDilate(A, If[0 < d ≤ 1, 1 - d, 0], B) → A'Segment(A, A') → eDilate(B, If[1 < d ≤ 2, 2 - d, 0], C) → B'Segment(B, B') → fDilate(C, If[2 < d ≤ 3, 3 - d, 0], A) → C'Segment(C, C') → gSegment(A, B) → hSegment(A, C) → iSegment(B, C) → jCircle(A, (0.15 * h)) → kIntersect(k, i, 1) → DIntersect(k, h, 1) → ECircleSector(A, E, D) → pRotate(A, If[3.5 < d ≤ 4.5, ((d - 3.5) * π / 3), 1.0471975511965976], A) → A'_1Rotate(A', If[3.5 < d ≤ 4.5, ((d - 3.5) * π / 3), 1.0471975511965976], A) → A''Segment(A'_1, A'') → e'Rotate(A, If[4.5 < d ≤ 5.5, ((-(d - 4.5)) * π / 3), -1.0471975511965976], B) → A'_2Rotate(A', If[4.5 < d ≤ 5.5, ((-(d - 4.5)) * π / 3), -1.0471975511965976], B) → A''_1Segment(A'_2, A''_1) → e'_1Dilate(A, If[6 < d ≤ 7, 7 - d, 0], B) → A'_3Vector(A, A'_3) → uTranslate(p, u) → p'CircleArc(A, E, D) → qRotate(p', If[7 < d ≤ 8, (((d - 7) * 2) * π / 3), 2.0943951023931953], B) → p''Circle(B, (0.15 * h)) → rIntersect(f, e'_1) → GIntersect(f, e'_1) → HIntersect(f, e'_1) → IIntersect(f, e'_1) → JIntersect(r, j, 1) → FIntersect(r, h, 1) → KCircleArc(B, F, K) → sDilate(B, If[8 < d ≤ 9, 9 - d, 0], C) → B'_1Vector(B, B'_1) → vTranslate(p'', v) → p'''Rotate(p''', If[9 < d ≤ 10, (((d - 9) * 2) * π / 3), 2.0943951023931953], C) → tCircle(C, (0.15 * h)) → c_1Intersect(g, e') → LIntersect(c_1, i) → M,Intersect(c_1, j) → N,Midpoint(h) → ODilate(C, If[10 < d ≤ 11, 11 - d, 0], O) → C'_1Segment(C, C'_1) → lCircle(O, (0.15 * h)) → d_1Segment(C, O) → mIntersect(d_1, m, 1) → PIntersect(d_1, h) → Q, RPolygon(A, O, C) → poly2, c_2, a_1, oIntersect(c_1, m) → S,CircleSector(C, S, N) → e_1CircleSector(O, R, P) → f_1Segment(O, B) → nRotate(f_1, If[11.25 < d ≤ 12.25, ((d - 11.25) * π / 2), 1.5708], O) → g_1Rotate(e_1, If[12.25 < d ≤ 13.25, ((-(d - 12.25)) * π / 6), -0.5236], C) → h_1CircleArc(C, S, N) → k_1CircleArc(O, R, P) → p_1Rotate(O, If[13.25 < d ≤ 14.25, ((-(d - 13.25)) * π), -3.141592653589793], O) → O'Rotate(B, If[13.25 < d ≤ 14.25, ((d - 13.25) * π), 3.14159], O) → B'_2Segment(O', B'_2) → n'Segment(O, B) → b_1Dilate(C, If[14.25 < d ≤ 15.25, 15.25 - d, 0], A) → C'_2Vector(C, C'_2) → wTranslate(h_1, w) → q_1Rotate(q_1, If[15.25 < d ≤ 16.25, (((-(d - 15.25)) * 4) * π / 3), -4.1887902047863905], A) → r_1Dilate(C, If[16.25 < d ≤ 17.25, 17.25 - d, 0], A) → C'_3Vector(C, C'_3) → u_1Translate(h_1, u_1) → s_1Rotate(s_1, If[17.25 < d ≤ 18.25, (((-(d - 17.25)) * 7) * π / 6), -3.665191429188092], A) → t_1Midpoint(g) → TRotate(O', If[18.25 < d ≤ 19.25, ((d - 18.25) * π / 3), 1.0471975511965976], A) → O''Rotate(B'_2, If[18.25 < d ≤ 19.25, ((d - 18.25) * π / 3), 1.0471975511965976], A) → USegment(O'', U) → n''Dilate(A, If[19.25 < d ≤ 20.25, 20.25 - d, 0], T) → A'_4Vector(A, A'_4) → v_1Translate(O', v_1) → O''_1Translate(B'_2, v_1) → VSegment(O''_1, V) → n''_1Rotate(O''_1, If[20.25 < d ≤ 21.25, ((d - 20.25) * π / 3), 1.0471975511965976], T) → WRotate(V, If[20.25 < d ≤ 21.25, ((d - 20.25) * π / 3), 1.0471975511965976], T) → V'Segment(W, V') → i_1