等腰梯形构造
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所属专题
Pyramid Puzzles
该范例演示了如何使用GeoGebra构造等腰梯形。涉及的核心数学概念包括几何作图、多边形和中点。通过使用Polygon、Midpoint等命令,可以构造出等腰梯形。适合初中及以上学生学习几何作图和等腰梯形的性质。
GeoGebra 命令及参数
Polygon(A, B, 4) → poly1, f_5, g, h, i, C, DPolygon(D, C, 4) → poly3, n, p, q, r, G, HPolygon(H, G, 4) → poly4, s, t, a_4, b_4, I, JPolygon(J, I, 4) → poly5, c_4, d_4, e_4, f_1, K, LPolygon(L, K, 4) → poly6, g_1, h_1, i_1, j_1, M, NPolygon(N, M, 4) → poly2, j, k, l, m, E, FMidpoint(i) → OMidpoint(r) → PMidpoint(b_4) → QMidpoint(f_1) → RMidpoint(j_1) → SMidpoint(m) → TMidpoint(m) → UPolygon(O, P, 4) → poly7, k_1, l_1, m_1, n_1, V, WPolygon(P, Q, 4) → poly8, p_1, q_1, r_1, s_1, Z, A_1Polygon(Q, R, 4) → poly9, t_1, a_1, b_1, c_1, B_1, C_1Polygon(R, S, 4) → poly10, d_1, e_1, f_2, g_2, D_1, E_1Polygon(S, T, 4) → poly11, h_2, i_2, j_2, k_2, F_1, G_1Midpoint(m_1) → H_1Midpoint(r_1) → I_1Midpoint(b_1) → J_1Polygon(H_1, I_1, 4) → poly12, l_2, m_2, n_2, p_2, K_1, L_1Polygon(I_1, J_1, 4) → poly13, q_2, r_2, s_2, t_2, M_1, N_1Midpoint(f_2) → P_1Midpoint(j_2) → Q_1Midpoint(j_2) → R_1Polygon(J_1, P_1, 4) → poly14, a_2, b_2, c_2, d_2, O_1, S_1Polygon(P_1, Q_1, 4) → poly15, e_2, f_3, g_3, h_3, T_1, U_1Midpoint(n_2) → V_1Midpoint(s_2) → W_1Midpoint(c_2) → Z_1Polygon(V_1, W_1, 4) → poly16, i_3, j_3, k_3, l_3, A_2, B_2Polygon(W_1, Z_1, 4) → poly17, m_3, n_3, p_3, q_3, C_2, D_2Midpoint(g_3) → E_2Polygon(Z_1, E_2, 4) → poly18, r_3, s_3, t_3, a_3, F_2, G_2Midpoint(k_3) → H_2Midpoint(p_3) → I_2Midpoint(t_3) → J_2Polygon(H_2, I_2, 4) → poly19, b_3, c_3, d_3, e_3, K_2, L_2Polygon(I_2, J_2, 4) → poly20, f_4, g_4, h_4, i_4, M_2, N_2Midpoint(d_3) → O_2Midpoint(h_4) → P_2Polygon(O_2, P_2, 4) → poly21, j_4, k_4, l_4, m_4, Q_2, R_2
AI 绘图提示语参考
绘制一个等腰梯形,首先通过四个顶点A、B、C、D构造一个四边形,然后找到AB和CD的中点O和P,接着以O和P为顶点构造两个新的四边形,以此类推,最终形成一个等腰梯形。
以上提示语为根据原始绘图命令整理而来,仅供参考。