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Fraction Division: a ÷ b Partitive

Fraction Division: a ÷ b Partitive
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2017-12-06 02:36
This example illustrates partitive division, where a ÷ b = a/b. Using GeoGebra commands such as Point, Segment, Sequence, and Polygon, the process of fraction division is dynamically demonstrated. Suitable for middle school and above students to learn about fraction division and partitive division.

GeoGebra Commands & Parameters

  1. Point(Segment[(x(D) + 2 / 5, y(D)), (x(D) + 1, y(D))]) → S
  2. Segment(A, (x(A) + 1, y(A))) → l1
  3. Point(Segment[(x(A) + 1 / 5, y(A)), (x(A) + 1, y(A))]) → P
  4. Segment(B, (x(B) + 1, y(B))) → l2
  5. Point(Segment[(x(B) + 2 / 6, y(B)), (x(B) + 1, y(B))]) → Q
  6. Point(Segment[(x(C) + 1 / 6 - 0.005, y(C)), (x(Q) - 1 / 6, y(C))]) → R
  7. Segment(C, (x(C) + 1, y(C))) → l3
  8. Sequence(Circle[((2.5 * (i - 1)), 0), 1], i, 1, a) → list1
  9. Sequence(Segment[((2.5 * a), 0), ((2.5 * a) - sin((j * θ)), cos((j * θ)))], j, 1, c - 1) → list2
  10. Segment(D, (x(D) + 1, y(D))) → l4
  11. Polygon((0.016528925619834656, -3), (1.2165289256198346, -3), (1.2165289256198346, -1.3), (0.016528925619834656, -1.3)) → poly1, e, g, h, i
  12. GCD(a, d) → k
  13. Segment(A, P) → j
  14. Segment(C, R) → l
  15. Segment(B, Q) → m
  16. Segment(D, S) → n
  17. Point(Segment[(x(A_1) + 1 / 7, y(A_1)), (x(A_1) + 1, y(A_1))]) → P_1
  18. Segment(A_1, P_1) → j_1
  19. Point(Segment[(x(D_1) + 2 / 5, y(D_1)), (x(D_1) + 1, y(D_1))]) → S_1
  20. Point(Segment[(x(A_2) + 1 / 7, y(A_2)), (x(A_2) + 1, y(A_2))]) → P_2
  21. GCD(a_1, d_1) → k_1
  22. Segment(A_2, P_2) → j_2
  23. Segment(D_1, S_1) → n_1
  24. Point(Segment[(x(D_2) + 2 / 5, y(D_2)), (x(D_2) + 1, y(D_2))]) → S_2
  25. Point(Segment[(x(A_3) + 1 / 7, y(A_3)), (x(A_3) + 1, y(A_3))]) → P_3
  26. GCD(a_2, d_2) → k_2
  27. Segment(A_3, P_3) → j_3
  28. Segment(D_2, S_2) → n_2
  29. Sequence(Sequence[CircleSector[(((-f) * sin((((2 * k) - 1) * θ / 2))) + (2.5 * (m - 1)), (f * cos((((2 * k) - 1) * θ / 2)))), (((-f) * sin((((2 * k) - 1) * θ / 2))) - sin(((k - 1) * θ)) + (2.5 * (m - 1)), (f * cos((((2 * k) - 1) * θ / 2))) + cos(((k - 1) * θ))), (((-f) * sin((((2 * k) - 1) * θ / 2))) - sin((k * θ)) + (2.5 * (m - 1)), (f * cos((((2 * k) - 1) * θ / 2))) + cos((k * θ)))], k, 1, 1], m, 1, a) → list4
  30. Sequence(Sequence[CircleSector[((f * sin((((2 * k) - 1) * θ / 2))) + (2.5 * (m - 1)), (f * cos((((2 * k) - 1) * θ / 2)))), ((f * sin((((2 * k) - 1) * θ / 2))) + sin((k * θ)) + (2.5 * (m - 1)), (f * cos((((2 * k) - 1) * θ / 2))) + cos((k * θ))), ((f * sin((((2 * k) - 1) * θ / 2))) + sin(((k - 1) * θ)) + (2.5 * (m - 1)), (f * cos((((2 * k) - 1) * θ / 2))) + cos(((k - 1) * θ)))], k, 1, b], m, 1, a) → list3

AI Drawing Prompt Reference

Draw a rectangle ABCD with point A at the origin, point B on the x-axis, point C in the first quadrant, and point D on the y-axis. Draw a line segment from point A to point P, which is 1/7 of the way along AB. Draw a line segment from point D to point S, which is 2/5 of the way along DC. Draw a line segment from point B to point Q, which is 2/6 of the way along BC. Draw a line segment from point C to point R, which is 1/6 of the way along CD. Draw a circle series with centers on the x-axis and radius 1, with centers spaced 2.5 units apart. Draw a sector series with each sector having a central angle of θ and radius f, with centers on the x-axis and centers spaced 2.5 units apart.
The prompt above was compiled from the original drawing commands and is for reference only.